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3 years ago

8

What does density have to do with heat?

2 answers:

joja [24]3 years ago

8 0

If you take a fluid (i.e. air or water) and heat it, the portion that is heated usually expands. The same mass takes up more volume and as a consequence the heated portion becomes less dense than the portion that is<span><span> not heated.</span> </span>

Vadim26 [7]3 years ago

7 0

Cooling a substance causes molecules to slow down and get<span> slightly closer together, occupying a smaller volume that results in an increase in </span>density<span>. Hot water is less dense and </span>will<span> float on room-temperature water. Cold water is more dense and </span>will<span>sink in room-temperature water.</span>

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1. If some unimaginable calamity destroyed the Sun, using the astronomical unit for the Earth-Sun distance and the value for the

Vsevolod [243]

Answer:

8 minutes and 20 seconds

Explanation:

Average Distance between Earth and Sun: 150 million km = $1.5 * 10^{8}$ km

Velocity of light: $3 * 10^{8} \ m/s = 3 * 10^{5} \ km/s$

Time = Distance/Speed

or Time = $1.5 * 10^{8} \ km$ / $3 * 10^{5} \ km/s$

= 5 * 100

= 500 seconds

⇒ Time = 8 minutes and 20 seconds

8 0

3 years ago

A football wide receiver rushes 16 m straight down the playing field in 2.9 s (in the positive direction). He is then hit and pu

vredina [299]

Answer:

a) $v_1=5.5172\ m.s^{-1}$

b) $v_2=-1.5152\ m.s^{-1}$

c) $v_3=4.6154\ m.s^{-1}$

d) $v_{avg}=3.8462\ m.s^{-1}$

Explanation:

Given:

distance down the field in the first interval, $d_1=16\ m$

time duration of the first interval, $t_1=2.9\ s$

distance down the field in the second interval, $d_2=-2.5\ m$

time duration of the second interval, $t_2=1.65\ s$

distance down the field in the third interval, $d_3=24\ m$

time duration of the third interval, $t_3=5.2\ s$

a)

velocity in the first interval:

$v_1=\frac{d_1}{t_1}$

$v_1=\frac{16}{2.9}$

$v_1=5.5172\ m.s^{-1}$

b)

velocity in the second interval:

$v_2=\frac{d_2}{t_2}$

$v_2=\frac{-2.5}{1.65}$

$v_2=-1.5152\ m.s^{-1}$

c)

velocity in the third interval:

$v_3=\frac{d_3}{t_3}$

$v_3=\frac{24}{5.2}$

$v_3=4.6154\ m.s^{-1}$

d)

We know that the average velocity is given as the total displacement per unit time.

$v_{avg}=\frac{d_1+d_2+d_3}{t_1+t_2+t_3}$

$v_{avg}=\frac{16-2.5+24}{2.9+1.65+5.2}$

$v_{avg}=3.8462\ m.s^{-1}$

3 0

3 years ago

Write the chemical formula for the following diagrams.

seraphim [82]

Answer:

hydrogen chloride...........

4 0

3 years ago

Calculate the speed of a dolphin that is observed swimming 75 meters in 5.0 seconds.

GarryVolchara [31]

Answer:

15 meters/second

Explanation:

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3 years ago

As you approach a bicyclist traveling in your lane, adjust your speed and position and do not pass if the road is too _______ fo

tatiyna

Answer:

correct answer is narrow

Explanation:

solution

when we pass someone riding bicycle ahead you then we should decrease our speed and increase the distance between you and bicyclist

and we should ride on road with very predictable manner and we should ride in straight line and if If road is too narrow for a bicycle

then we should ride vehicle to travel side by side so bicyclist should occupy lane until it safe

so here correct option is narrow

5 0

3 years ago