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Stells [14]
3 years ago
5

Wich part of the brian helps you keep balance so you don't fall flat on your face?

Physics
1 answer:
dalvyx [7]3 years ago
6 0

Answer:

Cerebellum .

Explanation:

The Cerebellum is the part of the brain that controls your walking and balance. If you need any more help feel free to reach out!

You might be interested in
Two very large parallel sheets are 5.00 cm apart. sheet a carries a uniform surface charge density of -9.70 μc/m2 , and sheet b,
MAVERICK [17]
Question is missing. Found on internet the complete text of the problem:

"<span>Two very large parallel sheets are 5.00 cm apart. Sheet A carries a uniform surface charge density of −9.70µC/m2, and sheet B, which is to the right or A, carries a uniform charge density of −11.5 µC/m2. Assume the sheets are large enough to be treated as infinite. Find the magnitude and direction of the net electric field these sheets produce at a point (a) 4.00 cm to the right of sheet A; (b) 4.00 cm to the left of sheet A; (c) 4.00 cm to the right of sheet B."

Solution:

(a) The electric field produced by a uniformly charged sheet at any distance is given by
</span>E= \frac{\sigma}{2 \epsilon _0}
where \sigma is the charge density and \epsilon _0 = 8.85\cdot 10^{-12} F/m is the vacuum permittivity.

First of all, let's compute the fields generated by the two sheets separately. The two densities of charge are \sigma_A = -9.70 \mu C/m^2=-9.70\cdot 10^{-6}C/m^2 and \sigma_B = -11.5 \mu C/m^2 = -11.5\cdot 10^{-6} C/m^2.

Sheet a gives an electric field of
E_A= \frac{\sigma_A}{2\epsilon _0}= \frac{-9.7\cdot 10^{-6} C/m^2}{2\cdot 8.85\cdot 10^{-12} F/m} = -5.48\cdot 10^5 V/m
where the negative sign means the field points towards sheet A, in any point of the space.

The electric field produced by sheet B is given by:
E_B = \frac{\sigma_A}{2\epsilon _0}= \frac{-11.5\cdot 10^{-6} C/m^2} {2\cdot 8.85\cdot 10^{-12} F/m} =-6.50\cdot 10^{5} V/m
and again, the negative sign means that the field at any point of the space points towards sheet B.

The point at which we have to compute the total field is at 4.00 cm right of sheet A. Since the two sheets are 5.00cm far apart, it means that this point is between the two sheets. Therefore, in this point the two fields point into opposite directions. Therefore, the total field is
E=E_1-E_2= -5.48\cdot 10^5 V/m - (-6.50\cdot 10^{5} V/m)=1.02\cdot 10^5 V/m
And the direction is towards sheet B, since it has a field with stronger intensity.

(b) Field at 4.00 cm to the left of sheet A: in this point of the space, the two fields point towards same direction (on the right, towards both sheet A and sheet B). So, the total field is simply the sum of the two fields:
E=E_1+E_2=-11.98\cdot 10^5 V/m
towards right.

(c) Field at 4.00 cm to the right of sheet B. As before, the two fields in this point have same direction (both towards left, pointing towards both sheet A and sheet B). And so, the total field is simply the sum of the two fields:
E=E_1+E_2=11.98 \cdot 10^5 V/m
towards left.
7 0
4 years ago
A cannon ball is shot straight upward with a velocity of 72.50 m/s. How high is the cannon ball above the ground 3.30 seconds af
disa [49]

Answer:

Explanation:

Given

Cannon is fired with a velocity of u=72.50\ m/s

Using Equation of motion

y=ut+\frac{1}{2}at^2

where

y=displacement

u=initial\ velocity

a=acceleration

t=time

after time t=3.3 s

y=72.50\times 3.3-\frac{1}{2}\times 9.8\times (3.3)^2

y=239.25-53.36

y=185.89\ m

So after 3.3 s cannon ball is at a height of 185.89 m

6 0
3 years ago
A softball player moving 3.89 m/s
Ahat [919]

Answer:

0.119 s

Explanation:

Given that

U=3.89\ m/s\\a=-1.44\ m/s^2\\S=4.8\ m

Lets take final speed of the softball after covering 4.8 m = V

We know that

V^2=U^2+2aS\\V^2=3.89^2-2\times 1.44\times 4.8\\V=3.7\ m/s

Also We know that

V=U+at\\

Putting the value of V ,U and a in the previous equation  We get

3.7=3.89-1.44\times t\\t=0.119\ s

Therefore slide time will be 0.119 s

3 0
4 years ago
What is gravity?
tester [92]

Answer:

<h2><em><u>a force that pulls objects to Earth</u></em></h2>
7 0
3 years ago
Read 2 more answers
a truck, initially traveling at a speed of 22 meters per second, increases speed at a constant rate of 2.4 meters per second2 fo
sineoko [7]
U = 22 m/s,  a = 2.4 m/s²,  t = 3.2 s

s = ut + (1/2)at²

s = 22*3.2 + (1/2)*2.4*3.2²

s = 70.4 + 12.228

s = 82.688 m.
6 0
4 years ago
Read 2 more answers
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