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3 years ago

What is gravity?

Physics

2 answers:

tester [92]3 years ago

7 0

Answer:

<h2><em><u>a force that pulls objects to Earth</u></em></h2>

dybincka [34]3 years ago

4 0

B !! Answer it correctly!

You might be interested in

Two small, identical conducting spheres repel each other with a force of 0.045 N when they are 0.15 m apart. After a conducting

Levart [38]

Answer:

$q_1 = \pm 1.68 \times 10^{-7} C$

$q_2 = \pm 6.68 \times 10^{-7} C$

Explanation:

As we know that the force between two small spheres is given as

$F = \frac{kq_1q_2}{r^2}$

here we know that

$q_1 , q_2$ = charges on two small spheres

r = distance between two spheres = 0.15 m

now the force between them is given as

$0.045 = \frac{(9\times 10^9)(q_1q_2)}{0.15^2}$

$q_1q_2 = 1.125 \times 10^{-13}$

now when two spheres are connected together then the charge on them is equally divided

$q = \frac{q_1+q_2}{2}$

now the force between them is given as

$F = \frac{k(\frac{q_1+q_2}{2})^2}{0.15^2}$

$0.070 = \frac{(9\times 10^9)(\frac{q_1+q_2}{2})^2}{0.15^2}$

$q_1 + q_2 = 8.37\times 10^{-7}$

so here we have

$q_1 = \pm 1.68 \times 10^{-7} C$

$q_2 = \pm 6.68 \times 10^{-7} C$

5 0

3 years ago

What is the acceleration of the motorcycle in section CD?

jenyasd209 [6]

Answer:

30m/s²

Explanation:

The acceleration of the motorcycle in section CD is the slope of the velocity - time graph.

Given that;

Initial velocity = 20m/s Time = 6s

Final velocity = 50m/s Time = 7s

The time interval = 7s - 6s = 1s

So;

Acceleration = $\frac{Change in velocity }{time}$ = $\frac{50 - 20}{1}$ = 30m/s²

6 0

3 years ago

A proton with a speed of 3.000×105 m/s has a circular orbit just outside a uniformly charged sphere of radius 7.00 cm. What is t

Rama09 [41]

To solve this problem we will apply the principles of energy conservation. The kinetic energy in the object must be maintained and transformed into the potential electrostatic energy. Therefore mathematically

$KE = PE$

$\frac{1}{2} mv^2 = \frac{kq_1q_2}{r}$

Here,

m = mass (At this case of the proton)

v = Velocity

k = Coulomb's constant

$q_{1,2}$ = Charge of each object

r= Distance between them

Rearranging to find the second charge we have that

$q_2 = \frac{\frac{1}{2} mv^2 r}{kq_1}$

Replacing,

$q_2 = \frac{\frac{1}{2}(1.67*10^{-27})(3*10^5)^2(7*10^{-2})}{(9*10^9)(1.6*10^{-19})}$

$q_2 = 3.6531nC$

Therefore the charge on the sphere is 3.6531nC

4 0

3 years ago

Arte-miy333 [17]

Answer:

the answer is C ----- it is the rate of change of velocity per unit time

Explanation:

acceleration

$= \frac{velocity(v)}{time(t)}$

3 0

3 years ago

It is known that the population mean for the verbal section of the SAT is 500 with a standard deviation of 100. In 2006, a sampl

kvasek [131]

Answer

given,

SAT is 500 with a standard deviation of 100.

a sample of 400 students whose family income was between $70,000 and $80,000 had an average verbal SAT score of 511.

sample mean = $\dfrac{standard\ deviation}{\sqrt{n}}$

= $\dfrac{100}{\sqrt{400}}$

= 5

95% confidence level is achieved within +/- 1.960 standard deviations.

1.960 standard deviations x 5 is equal to +/- 9.8

confidence interval = 511 - 9.8 --- 511 + 9.8

= 501.2-----520.8

4 0

3 years ago