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Answer:
CHCL3= 11.73 mL
CHBr3= 8.268 mL
Explanation:
Let x be the mL of CHCl3 and y be the mL of CHBr3, then we have:
y+x = 20 mL
1.492x+2.89y=2.07* 20.0 mL
Option B: 2, 8, 18, 32.
2 in the K shell, 8 in L shell, 18 in M shell and 32 in N shell.
Answer : The heat energy required to melt 2 kg of ice was, 667.7 kJ
Explanation :
First we have to calculate the moles of ice.
Now we have to calculate the heat energy.
As, heat energy required to melt 1 mole of ice = 6.01 kJ
So, heat energy required to melt 111.1 mole of ice = 111.1 × 6.01 kJ
= 667.7 kJ
Therefore, the heat energy required to melt 2 kg of ice was, 667.7 kJ
Empirical evidence is information acquired by observation or experimentation