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Sergeu [11.5K]
3 years ago
14

Why do plants need sap

Chemistry
2 answers:
Vinil7 [7]3 years ago
7 0
Plants don't need sap. Plants produce sap and attract bugs.
Furkat [3]3 years ago
7 0
Plants need sap becasue the sap helps them provide the food they need to survrive
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Fe(NO3)2 not sure how to get the oxidation numbers of all elements
Shtirlitz [24]
You must remember that oxidation number of hydrogen in acids is always +1, oxidation number of oxygen in oxides & acids is always -2... metals has always oxidation number on plus!

group NO3 comes from HNO3...and oxidation number of whole acid group is always on minus and equal to the amount of hydrogen atoms in this acid... so oxidation number of NO3 = -1

we have 2 NO3 groups so 2*(-1) = -2 and that is the reason why oxidation number of Fe in this formula must be +2... because sum of all elements always gives 0!

Now we could count of oxidation number for nitrogen... we write HNO3 and start counting from right to left:
3*(-2) from oxygens + 1 from hydrogen = -5
so nitrogen must have +5 oxidation number... because sum all in formula must be 0.


4 0
3 years ago
The following equation is an example of a ______________ reaction. 2 NaCl + F2 → 2 NaF + Cl2 ???
olga55 [171]

Answer:

double replacement is the answer

3 0
3 years ago
14. The following are a list of the four parts of John Dalton's atomic theory Indicate which of
Damm [24]

Answer:

1

all matter is made of tiny particles called atom

5 0
3 years ago
What seals the gauge line fitting to the gauge manifold
Rudik [331]

Tighten the screw clamp over the fitting with a screwdriver, and place another metal screw clamp over the other end of the rubber vacuum line.
7 0
3 years ago
When 20.0 grams of an unknown compound are dissolved in 500. grams of benzene, the freezing point of the resulting solution is 3
Lelu [443]

Answer: 120g/mol

Explanation:

The first step we are to take is to calculate the freezing point depression of the solution.

ΔT(f) = freezing point of pure solvent - freezing point of solution

ΔT(f) = 5.48 - 3.77

ΔT(f) = 1.71°C

Next we are to calculate the molal concentration of the solution using freezing point depression

ΔT(f) = K(f) * m

m = ΔT(f)/K(f)

m = 1.71/5.12

m = 0.333 molal

Now, we calculate the molecular weight of the unknown...

m = 0.333 mol = 0.333 mol X per kg of benzene

moles of X = 0.333 mol of X per kg of benzene * 0.5kg of benzene

moles of X = 0.1665

molecular weight of X = 20g of X/0.1665

molecular weight of X = 120/mol

5 0
3 years ago
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