Answer:
Explanation:
Combustion. Have fun with that.
1) Calcium carbonate contains 40.0% calcium by weight.
M(CaCO₃)=100.1 g/mol
M(Ca)=40.1 g/mol
w(Ca)=40.1/100.1=0.400 (40.0%)!
2) Mass fraction of this is excessive data.
3) The solution is:
m(Ca)=1.2 g
m(CaCO₃)=M(CaCO₃)*m(Ca)/M(Ca)
m(CaCO₃)=100.1g/mol*1.2g/40.1g/mol=3.0 g
Feo + 2H = H2O + Fe + 2 + CIO4-
this is ur answer. .
mrk me as brainlist
Answer: <u><em>True</em></u>
Explanation:
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