Answer:
2.30 liters.
Explanation:
- The balanced equation of the reaction is:
<em>Na₂O₂ + CO₂ → Na₂CO₃ + 1/2O₂,</em>
- It is clear that 1.0 mole of Na₂O₂ reacts with 1.0 mole of CO₂ to produce 1.0 mole of Na₂CO₃ and 0.5 mole of O₂.
- The no. of moles of CO₂ in (4.60 L) reacted can be calculated from the relation: <em>PV = nRT</em>.
P is the pressure of the gas (P = 1.0 atm at STP),
V is the volume of the gas (V = 4.60 L),
R is the general gas constant (R = 0.082 L.atm/mol.K),
T is the temperature of the gas (T = 273.0 K at STP).
∴ n = PV/RT = (1.0 atm)(4.6 L) / (0.082 L.atm/mol.K)(273.0 K) = 0.205 mol.
<u><em>Using cross multiplication:</em></u>
1.0 mole of CO₂ produces → 0.5 mole of O₂, from the stichiometry.
0.205 mole of CO₂ produces → ??? mole of O₂.
- The no. of moles of O₂ produced from 4.60 L of CO₂ = (0.5 mole)(0.205 mole) / (1.0 mole) = 0.103 mole.
- ∴ The volume of O₂ produced from 4.60 L of CO₂ = nRT/P = (0.103 mol)(0.082 L.atm/mol.K)(273.0 K) / (1.0 atm) = 2.30 liters.
