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Sladkaya [172]
2 years ago
7

What property appplies to the element radon?

Physics
1 answer:
Arlecino [84]2 years ago
8 0
Radioactive element
I. E..,ratio of neutrons is to protons is greater than 1.5
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A ball is projected into the air with 100 j of kinetic energy which is transformed to gravitational potential energy at the top
raketka [301]
<span>when it returns to its original level after encountering air resistance, its kinetic energy is decreased. 
In fact, part of the energy has been dissipated due to the air resistance.

The mechanical energy of the ball as it starts the motion is:
</span>E=K = 100 J
<span>where K is the kinetic energy, and where there is no potential energy since we use the initial height of the ball as reference level.
If there is no air resistance, this total energy is conserved, therefore when the ball returns to its original height, the kinetic energy will still be 100 J. However, because of the presence of the air resistance, the total mechanical energy is not conserved, and part of the total energy of the ball has been dissipated through the air. Therefore, when the ball returns to its original level, the kinetic energy will be less than 100 J.</span>
3 0
3 years ago
Why do astronauts need to wear pressurized suits in space?
SashulF [63]
The correct answer is C , because the space is vacuum and his body can explode and for this reason,  the astronaut need a special costum to be protected. It's the same on the moon, because there is no atmosphere 
6 0
3 years ago
A catapult with a spring constant of 10,000 N/m is used to launch a target from the deck of a ship. The spring is compressed a d
Mnenie [13.5K]

Answer:

(C) 40m/s

Explanation:

Given;

spring constant of the catapult, k = 10,000 N/m

compression of the spring, x = 0.5 m

mass of the launched object, m = 1.56 kg

Apply the principle of conservation of energy;

Elastic potential energy of the catapult = kinetic energy of the target launched.

¹/₂kx² = ¹/₂mv²

where;

v is the target's  velocity as it leaves the catapult

kx² = mv²

v² = kx² / m

v² = (10000 x 0.5²) / (1.56)

v² = 1602.56

v = √1602.56

v = 40.03 m/s

v ≅ 40 m/s

Therefore, the target's velocity as it leaves the spring is 40 m/s

6 0
2 years ago
You would like a pendulum that swings back and forth once every 2 seconds, but the one you have swings once every 1.9 seconds. W
patriot [66]

Your pendulum does a complete swing in 1.9 seconds.  You want to SLOW IT DOWN so it takes 2.0 seconds.

Longer pendulums swing slower.

You need to <em>make your pendulum slightly longer</em>.

If your pendulum is hanging by a thread or a thin string, then its speed doesn't depend at all on the weight at the bottom.  You can add weight or cut some off, and it won't change the speed a bit.  

6 0
3 years ago
Describe characteristics and identify oxidation-reduction(redox) reactions. <br><br> plz and thx
mars1129 [50]

Answer:

I hope This helps

Explanation:

The majority of oxidation-reduction (redox) reactions share two critical features. One is that a reduction happens in both, while equivalent oxidation occurs; they are combined.

8 0
2 years ago
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