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kolezko [41]
3 years ago
6

If racing alcohol has a mass density of 790kg/m3, what mass will a 1250-litre tank hold?

Physics
1 answer:
Marina86 [1]3 years ago
3 0
Density = Mass per unit Volume
that is,
D = m / V

Now,
We've been provided with,

Density = 790 kg/m³
Volume = 1250 litres = 1.250 m³

Now,
density = \frac{mass}{volume} \\ 790 = \frac{m}{1.250} \\ 790 \times 1.250 = m \\ m = 790 \times 1.250 \\ m = 790 \times \frac{1250}{1000} \\ m = 790 \times \frac{5}{4} \\ m = 197.5 \times 5 \\ m = \frac{1975}{10} \times 5 \\ m = \frac{1975}{2} = 987.5 \: kg

987.5 kg of mass will a 1250 litres tank will hold.

Please Mark It As Brainliest Answer_
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An object is 16.0cm to the left of a lens. The lens forms an image 36.0cm to the right of the lens.
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We can find the focal length of the lens by using the lens equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

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q = 36.0 cm is the distance of the image from the lens (taken with positive sign since it is on the opposide side to the image, so it is a real image)

Solving the equation for f:

\frac{1}{f}=\frac{1}{16.0 cm}+\frac{1}{36.0 cm}=0.09 cm^{-1}\\f=\frac{1}{0.09 cm^{-1}}=11.1 cm

B) Converging

The focal length is:

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In this case, the focal length is positive, so it is a converging lens.

C) 18.0 mm

The magnification equation states that:

\frac{h_i}{h_o}=-\frac{q}{p}

where

h_i is the heigth of the image

h_o is the height of the object

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Solving the formula for h_i, we find

h_i = -h_o \frac{q}{p}=-(8.00 mm)\frac{36.0 cm}{16.0 cm}=-18.0 mm

So the image is 18 mm high.

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From the magnification equation we have that:

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4 0
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Answer:

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