3 years ago

If the speed of a ball increased from 1m/s to 4m/s by how much would kinetic energy increase

1 answer:

3 0

Kinetic energy = (1/2) to mass and speed^2.

The formula of speed, and it will be squared.

multiply (4)^2 and it equals to 16.

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the half-life of iodine-131 is 8.1 days. how much time had passed if i only have one-fourth of the original sample?

morpeh [17]

Answer:

16.2 days

Explanation:

Find the number of halflives:

1/2 * 1/2 = 1/4 so two halflives have passed

2 * 8.1 days = 16.2 days

8 0

1 year ago

Based on the law of conservation of energy, how can we reasonably improve a machine’s ability to do work?

fiasKO [112]

C. Reduce the friction between its moving parts.

6 0

3 years ago

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A diver comes off a board with arms straight up and legs straight down, giving her a moment of inertia about her rotation axis o

mihalych1998 [28]

Answer:

θ₁ = 0.5 revolution

Explanation:

We will use the conservation of angular momentum as follows:

$L_1=L_2\\I_1\omega_1=I_2\omega_2$

where,

I₁ = initial moment of inertia = 18 kg.m²

I₂ = Final moment of inertia = 3.6 kg.m²

ω₁ = initial angular velocity = ?

ω₂ = Final Angular velocity = $\frac{\theta_2}{t_2} = \frac{2\ rev}{1.2\ s}$ = 1.67 rev/s

Therefore,

$(18\ kg.m^2)\omega_1 = (3.6\ kg.m^2)(1.67\ rev/s)\\\\\omega_1 = \frac{(3.6\ kg.m^2)(1.67\ rev/s)}{(18\ kg.m^2)}\\\\\omega_1 = \frac{\theta_1}{t_1} = 0.333\ rev/s\\\\\theta_1 = (0.333\ rev/s)t_1$

where,

θ₁ = revolutions if she had not tucked at all = ?

t₁ = time = 1.5 s

Therefore,

$\theta_1 = (0.333\ rev/s)(1.5\ s)\\$

θ₁ = 0.5 revolution

4 0

3 years ago

A rectangular plate has a length of (21.7 ± 0.2) cm and a width of (8.2 ± 0.1) cm. Calculate the area of the plate, including it

Grace [21]

Answer:

(177.94 ± 3.81) cm^2

Explanation:

l + Δl = 21.7 ± 0.2 cm

b + Δb = 8.2 ± 0.1 cm

Area, A = l x b = 21.7 x 8.2 = 177.94 cm^2

Now use error propagation

$\frac{\Delta A}{A}=\frac{\Delta l}{l}+\frac{\Delta b}{b}$

$\frac{\Delta A}{A}=\frac{0.2}{21.7}+\frac{0.1}{8.2}$

$\Delta A=177.94 \times \left ( 0.0092 + 0.0122 \right )=3.81$

So, the area with the error limits is written as

A + ΔA = (177.94 ± 3.81) cm^2

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3 years ago

Which action can be explained by physics

Lunna [17]

Dropping two objects and seeing them hit the ground at the same time

3 0

4 years ago

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