If the speed of a ball increased from 1m/s to 4m/s by how much would kinetic energy increase
1 answer:
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Answer:
7.11x10^-3
Explanation:
We are to get the volume rate of flows
1/2pv1² + pl = 1/2pv2²
Such that A1V1 = A2V2
V1 = A2V2/A1
From the attachment I uploaded, we have a formula named equation 1 from which I have plugged in these values
P2 = 33000
P2 = 24000
P = 1000
r2 = 2.25
r1 = 4
When we put these values into the equation,
V2 = 4.47
A2V2 = pi(0.0225)²x4.47
= 7.7x19^-3m³/s
Answer:
The water is flowing at the rate of 28.04 m/s.
Explanation:
Given;
Height of sea water, z₁ = 10.5 m
gauge pressure, = 2.95 atm
Atmospheric pressure, = 101325 Pa
To determine the speed of the water, apply Bernoulli's equation;
where;
P₁ =
P₂ =
v₁ = 0
z₂ = 0
Substitute in these values and the Bernoulli's equation will reduce to;
where;
is the density of seawater = 1030 kg/m³
Therefore, the water is flowing at the rate of 28.04 m/s.