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Burka [1]
3 years ago
6

Need chem help asap

Chemistry
1 answer:
gavmur [86]3 years ago
5 0

Oh I’m so4+ds2=563

Which is the answer

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Tetrachloromethane,CC15,is classified as a
prohojiy [21]
Correct Answer: compound because the atoms of the elements are combined in a fixed proportion.
7 0
3 years ago
A 3.4 g sample of an unknown monoprotic organic acid composed of C,H, and O is burned in air to produce 8.58 grams of carbon dio
Pavlova-9 [17]

Answer:

C_7H_6O_2

Explanation:

Hello there!

In this case, we can divide the problem in three stages: (1) determine the empirical formula with the combustion analysis, (2) compute the molar mass of acid via the moles of the acid in the neutralization and (3) determine the molecular formula.

(1) In this case, since 8.58 g of carbon dioxide are released, we can first compute the moles of carbon in the compound:

n_C=8.58gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2}=0.195molC

And the moles of hydrogen due to the produced 1.50 grams of water:

n_H=1.50gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O}  =0.166molH

Next, to compute the mass and moles of oxygen, we need to use the initial 3.4 g of the acid:

m_O=3.4g-0.195molC*\frac{12.01gC}{1molC}-0.166molH*\frac{1.01gH}{1molH} =0.89gO\\\\n_O=0.89gO*\frac{1molO}{16.0gO}=0.0556molO

Thus, the subscripts in the empirical formula are:

C=\frac{0.195}{0.0556}=3.5 \\\\H=\frac{0.166}{0.0556}=3\\\\O=\frac{0.0556}{0.0556}=1\\\\C_7H_6O_2

As they cannot be fractions.

(2) In this case, since the acid is monoprotic, we can compute the moles by multiplying the concentration and volume of KOH:

n_{KOH}=0.279L*0.1mol/L\\\\n_{KOH}=0.0279mol

Which are equal to the moles of the acid:

n_{acid}=0.0279mol

And the molar mass:

MM_{acid}=\frac{3.4g}{0.0279mol} =121.86g/mol

(3) Finally, since the molar mass of the empirical formula is:

7*12.01 + 6*1.01 + 2*16.00 = 122.13 g/mol

Thus, since the ratio of molar masses is 122.86/122.13 = 1, we infer that the empirical formula equals the molecular one:

C_7H_6O_2

Best regards!

8 0
3 years ago
What is the mass of 1.7 × 1023 atoms of zinc
fiasKO [112]

We are given with a compound, Zinc (Zn) having a 1.7 x 10 ^23 atoms. We are tasked to solve for it's corresponding mass in g. We need to find first the molecular weight of Zinc, that is

Zn= 65.38 g/mol

Not that 1 mol=6.022x10^{23} atoms, hence,

1.7 x 10 ^23 atoms x 1 mol/6.022x10^{23} atoms x65.38 g/ 1mol

=18.456 g of Zn

 

Therefore, the mass of Zinc 18.456 g

3 0
3 years ago
Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions:
cupoosta [38]
MgO
MgI2
PbO2
PbI4

These are the possible compounds
4 0
3 years ago
Read 2 more answers
If an atom of Oxygen (8 protons, 8 neutrons, and 8 electrons) gains two electrons, what is the charge of the ion formed?
Alexxx [7]

Answer:

It becomes negative

Explanation:

protons carry a positive charge

neutrons carry a neutral charge

electrons carry a negative charge

if we add 2 more electrons, the charge of the ion becomes negative

thank you.

4 0
3 years ago
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