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lutik1710 [3]
2 years ago
10

The fertilization in __________happens outside the female's body​

Chemistry
1 answer:
denis23 [38]2 years ago
7 0

Answer:

Frogs

Explanation:

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Percent Error Problems – Find the percent error for each problem below.
Citrus2011 [14]

% error = 3.4 %

Percent error = |accepted value - experimental value|/accepted value × 100%

∴ % error = |355 mL – 343 mL|/355 mL × 100 % = |12|/355 × 100 % = 3.4 %

5 0
3 years ago
Which statement describes global winds?
sergejj [24]

Answer:

They blow away from poles to the equator.

Explanation:

Hello,

In this case, we must take into account that global wind systems are formed by the constant increase in the temperature of the Earth’s surface. Thus, they drive the oceans’ surface currents. In such a way, we can say wind is the basic movement of air from an area of higher pressure to an area of lower pressure, for that reason they blow away from the poles to the equator.

Best regards.

6 0
3 years ago
Read 2 more answers
How many oxygen atoms are contained in 2.74 g of Al2(SO4)3?
abruzzese [7]

Answer:

5.79 × 10^23 Oxygen atoms

Explanation:

Number of Oxygen atom in the compound = 4×3 = 12

Molar mass of Al2(SO4)3 = 342 g/mol.

No of mole = mass/molar mass = 2.74/342 = 8.01×10^-03 mole

2.74g of Al2(SO4)3 × 1 mole of Al2 (SO4)3 / 342g of Al2 (SO4)3 * 12 mole of Oxygen/ 1mole of Al(SO4)3 * 6.02×10^23 Oxygen atom/ 1 mole of Oxygen

= 5.79×10^23 Oxygen atoms

3 0
3 years ago
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Two moles of magnesium (Mg) and five moles of oxygen (O2) are placed in a reaction vessel. When magnesium is ignited, it reacts
SOVA2 [1]

Answer:

\boxed{\text{Mg is the limiting reactant}}

Explanation:

We are given the amounts of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble the data in one place.

           2Mg + O₂ ⟶ 2MgO

n/mol:    2       5

Calculate the moles of MgO we can obtain from each reactant.

From Mg:  

The molar ratio of MgO:Mg is 2:2

\text{Moles of MgO} = \text{2 mol Mg} \times \dfrac{\text{2 mol MgO}}{\text{2 mol Mg}} = \text{2 mol MgO}

From O₂:  

The molar ratio of MgO:O₂ is 2:1.

\text{Moles of MgO} = \text{5 mol O}_{2} \times \dfrac{\text{2 mol MgO}}{\text{1 mol O}_{2}} = \text{10 mol MgO}\\\\\boxed{\textbf{Mg is the limiting reactant}} \text{ because it gives the smaller amount of MgO}

6 0
3 years ago
The modern-day quantum model of the atom is better than John Dalton’s model because it
Licemer1 [7]
The modern day model of an atom has a lot of questions answered about it answered and is very accurate while John's version was a very early model before technology was advanced enough to get more information on it so it was very basic and not as accurate as today's model. Hope this helps!
7 0
3 years ago
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