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3 years ago

Please help me asap!!!

Chemistry

1 answer:

Nata [24]3 years ago

5 0

The temperature rose. so kinetic energy increase. the answer is A. concentration will not affected

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Fill in the word that completes each sentence. Food contains a sugar called , which is broken down in a process called cellular

Pie

Answer:

glucose

respiration

oxygen

Explanation:

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3 years ago

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Which of the following is a carboxylic acid?

MrRissso [65]

Answer:d

Explanation:

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2 years ago

1. The attraction between the hydrogen atom in one water molecule and the oxygen molecule in another is

Rudik [331]

Answer:

ionic bond is formed when there is transfer of electrons and is composed of a positive cation and a negative anion

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3 years ago

Pure acetic acid (hc2h3o2) is a liquid and is known as glacial acetic acid. calculate the molarity of a solution prepared by dis

Alexandra [31]

In order to find the molarity of the solution, we first require the moles of acetic acid added. For this,we need the mass which is:

Mass = volume * density

Mass = 50 * 1.05
Mass = 52.5 grams

Moles = mass / molecular weight

Moles = 52.5 / 60.05
Moles = 0.874 mol

Next, we know that the molarity of a solution is:

Molarity = moles / liter
Molarity = 0.874 / 0.5

Molarity = 1.75 M

3 0

3 years ago

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A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.

BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

$\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\ &=185.59\text{ g/mol} \end{aligned}$

Dimensional Analysis:

$\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }$

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0

3 years ago