Answer:
C: 
Explanation:
we can use the molarity equation

so to find M we plug in what we know, which is 6 moles of NaCl and 2 L of water, which gives us:

Answer:
Darker colored items absorb more of the sunlight.
Explanation:
Lighter colored item tend to reflect more of the sunlight
pH of solution = 13.033
<h3>Further explanation</h3>
Given
2.31 g Ba(OH)₂
250 ml water
Required
pH of solution
Solution
Barium hydroxide is fully ionized, means that Ba(OH)₂ is a strong base
So we use a strong base formula to find the pH
[OH ⁻] = b. Mb where
b = number of OH⁻
/base valence
Mb = strong base concentration
Molarity of Ba(OH)₂(MW=171.34 g/mol) :

Ba(OH)₂ ⇒ Ba²⁺ + 2OH⁻(b=valence=2)
[OH⁻]= 2 . 0.054
[OH⁻] = 0.108
pOH= - log 0.108
pOH=0.967
pOH+pH=14
pH=14-0.967
pH=13.033
Answer:
25,272
Explanation:
Multiply 9.0 x 108 = 972
Multiply 3.0 x 10 = 30 - 4 = 26
Lastly, multiply 972 x 26= 25,272