Answer:
C:
Explanation:
we can use the molarity equation
so to find M we plug in what we know, which is 6 moles of NaCl and 2 L of water, which gives us:
Atoms of the same element can have different forms; for example, carbon-12 and carbon-14.
1 answer:
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pH of solution = 13.033
<h3>Further explanation</h3>Given
2.31 g Ba(OH)₂
250 ml water
Required
pH of solution
Solution
Barium hydroxide is fully ionized, means that Ba(OH)₂ is a strong base
So we use a strong base formula to find the pH
[OH ⁻] = b. Mb where
b = number of OH⁻ /base valence
Mb = strong base concentration
Molarity of Ba(OH)₂(MW=171.34 g/mol) :
Ba(OH)₂ ⇒ Ba²⁺ + 2OH⁻(b=valence=2)
[OH⁻]= 2 . 0.054
[OH⁻] = 0.108
pOH= - log 0.108
pOH=0.967
pOH+pH=14
pH=14-0.967
pH=13.033
Answer:
Here is the answer:
Explanation:
