Answer:
See explanation
Explanation:
We can describe electrons using four sets of quantum numbers;
principal quantum number (n)
orbital quantum number (l)
magnetic quantum number (ml)
spin quantum number (ms)
Since no two electrons in an atom can have the same value for all four quantum numbers according to Pauli exclusion theory, for the orbitals given one possible value for each quantum number is shown below;
For 1s-
n = 1, l= 0, ml = 0, ms= 1/2
For 2s-
n= 2, l =0, ml=0, ms=1/2
For 1s and 2s orbitals, there is only one possible value for ml which is zero.
Answer:
Choice A: approximately
.
Explanation:
Note that the unit of concentration,
, typically refers to moles per liter (that is:
.)
On the other hand, the volume of the two solutions in this question are apparently given in
, which is the same as
(that is:
.) Convert the unit of volume to liters:
.
.
Calculate the number of moles of
formula units in that
of the
solution:
.
Note that
(sulfuric acid) is a diprotic acid. When one mole of
completely dissolves in water, two moles of
ions will be released.
On the other hand,
(sodium hydroxide) is a monoprotic base. When one mole of
formula units completely dissolve in water, only one mole of
ions will be released.
ions and
ions neutralize each other at a one-to-one ratio. Therefore, when one mole of the diprotic acid
dissolves in water completely, it will take two moles of
to neutralize that two moles of
produced. On the other hand, two moles formula units of the monoprotic base
will be required to produce that two moles of
. Therefore,
and
formula units would neutralize each other at a two-to-one ratio.
.
.
Previous calculations show that
of
was produced. Calculate the number of moles of
formula units required to neutralize that
.
Calculate the concentration of a
solution that contains exactly
of
formula units:
.
Answer:
The volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L
Explanation:
Given data:
Number of moles of HF = 6.62×10⁻³ mol
Volume of HF in litter at STP = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Standard temperature = 273 K
Standard pressure = 1 atm
Now we will put the values in formula.
1 atm × V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K × 273 K
V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K × 273 K / 1 atm
V = 148.38×10⁻³ L
Thus, the volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L.
Answer: Option (D) is the correct answer.
Explanation:
Atomic number of lithium is 3 and electrons in its shell are distributed as 2, 1. Atomic number of chlorine is 17 and electrons in its shell are distributed as 2, 8, 7.
Thus, we can see that lithium has 1 extra electron and chlorine has deficiency of 1 electron. Therefore, in order to gain stability lithium will transfer its 1 extra electron to chlorine atom.
Thus, we can conclude that electrons are transferred from the lithium atom to the chlorine atom.