1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
antiseptic1488 [7]
2 years ago
6

A scientific experiment requires that the temperature be lowered at a steady and gradual rate. The beginning temperature is 34°

C and the temperature is lowered 2 degrees per day. What linear function in the form represents the temperature in degrees, t, after d days.
Chemistry
1 answer:
Finger [1]2 years ago
6 0

The linear equation formed can be given as                        

\rm F(t)=34-2t

Linear function is the relationship between the variable, with the graph being a straight line. The equation for a linear function is given as:

\rm F=mc+b

<h3>Linear function for temperature and time</h3>

The initial temperature of the experiment is given as 34 degree Celsius and is given by t.

The time after which temperature is measured is t.

The time for which the lowering observed is 2 degrees per day.

The linear equation formed can be given as:

\rm F(t)=34-2t

Learn more about linear equation, here:

brainly.com/question/11897796

You might be interested in
The tendency of a moving object to continue moving in a straight line or a stationary object to remain in place is called
Mademuasel [1]
The tendency of a moving object to continue moving in a straight line or a stationary object to remain in place is called inertia.

Answer: C) or the third option.
5 0
3 years ago
Read 2 more answers
At equilibrium, a 1.0 L reaction vessel contains 2.3 mol of Mg(OH)₂ and 0.170 mol of OH⁻. What is the equilibrium concentration
Andru [333]

The value of X for this chemical reaction is 1.65 x 10⁻⁴

<u>Explanation:</u>

Mg (OH)₂(s) <==> Mg²⁺+(aq) + 2OH₋₁(aq)  

Kc= 1.80x10⁻¹¹

KC = [Mg²⁺][OH-]²

Let us assume

Put X = [Mg²⁺] and  2x = [OH-]

1.80x10-11 = (X) (2X)²

1.80x10-11 = 4X³

X³ = 4.5x10⁻¹²

On simplifying the equation we get,

X = 1.65 x 10⁻⁴

The value of X for this chemical reaction is 1.65 x 10⁻⁴

7 0
3 years ago
Calculate the percent oxygen in potassium chlorate (KClO3)
andreev551 [17]

Molar Mass of KCLO3

= 39 + 35.5 + 48 g

= 122.5 g .

So , percentage of Potassium ( K )

= 39 / 122.5 * 100 %

= 31.83 %

Now , percentage of Chlorine ( Cl )

= 35.5 / 122.5 * 100 %

= 28.97 %

So, finally, percentage of Oxygen ( O )

= 48 / 122.5 * 100 %

= 39.18 %

7 0
3 years ago
Read 2 more answers
What does it mean if data are reproducible but not accurate?
egoroff_w [7]
If data results a reproducible but not accurate, it means that there was a high level of precision, but not complete accuracy.
3 0
4 years ago
Read 2 more answers
Which of the following is an element?<br> A. MgBr<br><br> B. HCl<br><br> C.O<br><br> .D. Cu(SO4)3
DanielleElmas [232]
The answer is c. the others are compounds.
5 0
3 years ago
Read 2 more answers
Other questions:
  • You've just solved a problem and the answer is the mass of an electron, me=9.11×10−31kilograms. How would you enter this number
    12·1 answer
  • How many hours of sunlight is the South Pole receiving during this time?
    7·1 answer
  • Why does warm soda go flat faster than chilled soda?
    12·2 answers
  • Answer in the correct significant figures: 9.66 / 0.33
    8·1 answer
  • An unbalanced chemical equation for the reaction of boron fluoride with lithium sulfite is shown below.
    12·1 answer
  • Draw the product of the following reaction between a ketone and an alcohol.
    9·1 answer
  • Please help me I will give you the brain thing and extra points.
    9·2 answers
  • How many atoms are in 4.5 g of AICI3?
    11·1 answer
  • First person with the right answer gets brainliest thanks (btw the numbers on the right are the answers choose the right one)
    9·1 answer
  • "Deka" is a decimal unit prefix in the metric system, denoting a factor of
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!