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antiseptic1488 [7]
2 years ago
6

A scientific experiment requires that the temperature be lowered at a steady and gradual rate. The beginning temperature is 34°

C and the temperature is lowered 2 degrees per day. What linear function in the form represents the temperature in degrees, t, after d days.
Chemistry
1 answer:
Finger [1]2 years ago
6 0

The linear equation formed can be given as                        

\rm F(t)=34-2t

Linear function is the relationship between the variable, with the graph being a straight line. The equation for a linear function is given as:

\rm F=mc+b

<h3>Linear function for temperature and time</h3>

The initial temperature of the experiment is given as 34 degree Celsius and is given by t.

The time after which temperature is measured is t.

The time for which the lowering observed is 2 degrees per day.

The linear equation formed can be given as:

\rm F(t)=34-2t

Learn more about linear equation, here:

brainly.com/question/11897796

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the pressure in a sealed plastic container is 108 kPa at 41 degrees Celsius. What is the pressure when the temperature drops to
Katarina [22]

<u>Answer:</u> The new pressure will be 101.46 kPa.

<u>Explanation:</u>

To calculate the new pressure, we use the equation given by Gay-Lussac Law. This law states that pressure is directly proportional to the temperature of the gas at constant volume.

The equation given by this law is:

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are initial pressure and temperature.

P_2\text{ and }T_2 are final pressure and temperature.

We are given:

By using conversion factor:   T(K)=T(^oC)+273

P_1=108kPa\\T_1=41^oC=314K\\P_2=?kPa\\T_2=22^oC=295K

Putting values in above equation, we get:

\frac{108kPa}{314K}=\frac{P_2}{295K}\\\\P_2=101.46kPa

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3 0
3 years ago
An organic acid was analyzed and the following percent composition was obtained: 68.85% carbon, 4.9% hydrogen, and 26.2% oxygen.
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Answer:

The molecular formula of the compound is: C14H12O4

Explanation:

Step 1: find molality

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molality (m) = ΔT/Kf = -2.13/-5.12 = 0.416 m

step 2: find number of moles

m = number of moles (n)/Kg solvent which is the benzene

n = molality x Kg solvent = 0.416 molality X (10 x 10^-3 Kg) = 0.00416 mole

Step 3: find molecular mass of the organic compound

n = mass/Molecular mass = m/Mm

Mm = m/n = 1.02/0.00416 = 245.19 g/mole of organic compound molecular formula

Step 4: find number of mole of each compound

let consider it being in 100g where each % will correspond to the mass of the element in 100g of the compound.

C = mass/molar mass = 68.85/12.01 = 5.7327 mole

H = mass/molar mass = 4.9/1.01 = 4.8515 mole

O = mass/molar mass = 26.2/16 = 1.6375 mole

Step 5: divide by smallest number of mole

C = 5.7327/1.6375 = 3.5 = 7/2

H = 4.8515/1.6375 = 3

O = 1.6375/1.6375 = 1

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multiply by two to remove the fraction: C7H6O2 in which the empirical molecular mass = 122.13 g/mole

to find the factor for the molecular formula x = Mm of molecular/Mm of empirical = 245.19/122.13 = 2

Multiply the empirical by 2 = 2 x (C7H6O2) = C14H12O4

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