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Pachacha [2.7K]
4 years ago
14

Three point charges (some positive and some negative) are fixed to the corners of the same square in various ways, as the drawin

gs show. Each charge, no matter what its algebraic sign, has the same magnitude. In which arrangement (if any) does the net electric field at the center of the square have the greatest magnitude?
Physics
1 answer:
strojnjashka [21]4 years ago
6 0

Answer:

The magnitude of the net field located at the center of the square is the same in every of arrangement of the charges.

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Determine the focal length of a plano-concave lens (refractive index n =1.5) with 24 cm radius of curvature on its curve surface
tatyana61 [14]

Answer:

Option 3: -48 cm

Explanation:

We are given:

refractive index; n = 1.5

radius of curvature; r2 = 24 cm

Formula for the focal length is given as;

1/f = (n - 1) × [(1/r1) - (1/r2)]

As r1 tends to infinity, 1/r1 = 0

Thus,we now have;

1/f = (n - 1) × (-1/r2)

Plugging in the relevant values;

1/f = (1.5 - 1) × (-1/24)

1/f = -0.02083333333

f = -1/0.02083333333

f = -48 cm

3 0
3 years ago
(Please help, will give thanks + brainliest answer)
Bond [772]

Answer:

A) 1.9m/s

Explanation:

Use the equation v=d/t

The time is 10 seconds. The distance is more complicated because it’s a circle so u use the equation for circumference C=2•pi•r. So you just do the circumference over time and get the answer. Hope this helps

8 0
4 years ago
My Notes A container is divided into two equal compartments by a partition. One compartment is initially filled with helium at a
Ostrovityanka [42]

Answer:

final-temperature = T_{f} = 252.51K

Explanation:

we can solve this problem by using the first law of thermodynamics.

    \Delta U= Q-W

Q= heat added

U= internal energy

W= work done by system

                        E_{final}= E_{initial}

<u> C_{v} (N_{2}) C_{v}(He) T_{f} =C_{v}( N_{2}) T_{N_{2} } C_{v} (He) T_{He}    (1)</u>

C_{v}(N_{2})=1.04\frac{KJ}{Kg K}

C_{v}(He)=5.193\frac{KJ}{Kg K}

now

From equation 1

T_{f}=\frac{C_{v}( N_{2}) T_{N_{2} } C_{v} (He) T_{He}}{C_{v} (N_{2}) C_{v}(He)}

T_{f} = \frac{315\times1.04+5.193\times240}{1.04+5.193}

T_{f} = 252.51K

4 0
4 years ago
The electric field strength E is measured as:
soldi70 [24.7K]
The correct answer is
<span>force per unit charge.

In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
</span>E= \frac{F}{q}
where
E is the electric field strength
F is the electric force experienced by the charge
q is the positive test charge.
4 0
3 years ago
The isotope 14 C has a half life of 5700 years. If the
nataly862011 [7]

Answer:

the sample is approximately 4065 years old

4 0
3 years ago
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