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3 years ago

All of the following are true concerning enzymes, except that they:

Chemistry

1 answer:

suter [353]3 years ago

8 0

Answer:

D (or E If properly listed to include the active site option)

Explanation:

A. Is true

Enzymes are organically biochemical catalyst and thus they can speed up the rate of chemical reaction in the body

B is true

They are catalysts as said earlier

C is true

They have active sites. An enzyme does not act on all substrates. They have particular group on which they can act. For example, we have carbohydrates enzymes that act on carbohydrates substrate only. This enzymes have no business acting on a protein substrate.

D. Enzymes are proteins

One of the important characteristics of enzymes is that they are protenious in nature

E. This is wrong. Enzymes like any over catalyst are not consumed in the course of the biochemical reaction

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If 16.00 g of O₂ reacts with 80.00 g NO, how many grams of NO₂ are produced? (enter only the value, round to whole number)

Norma-Jean [14]

Answer:

46 g

Explanation:

The balanced equation of the reaction between O and NO is

2 NO + O₂ ⇔ 2 NO₂

Now, you need to find the limiting reagent. Find the moles of each reactant and divide the moles by the coefficient in the equation.

NO: (80 g)/(30.006 g/mol) = 2.666 mol

(2.666 mol)/2 = 1.333

O₂: (16 g)/(31.998 g/mol) = 0.500 mol

(0.500 mol)/1 = 0.500 mol

Since O₂ is smaller, this is the limiting reagent.

The amount of NO₂ produced will depend on the limiting reagent. You need to look at the equation to determine the ratio. For every mole of O₂ reacted, 2 moles of NO₂ are produced.

To find grams of NO₂ produced, multiply moles of O₂ by the ratio of NO₂ to O₂. Then, convert moles of NO₂ to find grams.

0.500 mol O₂ × (2 mol NO₂/1 mol O₂) = 1.000 mol NO₂

1.000 mol × 46.005 g/mol = 46.005 g

You will produce 46 g of NO₂.

6 0

3 years ago

The first excited electronic energy level of the helium atom is 3.13 x 10-18 J above the ground level. Estimate the temperature

salantis [7]

Answer:

75603.86473 K

Explanation:

Given that:

The 1st excited electronic energy level of He atom = 3.13 × 10⁻¹⁸ J

The objective of this question is to estimate the temperature at which the ratio of the population will be 5.0 between the first excited state to the ground state.

The formula for estimating the ratio of population in 1st excited state to the ground state can be computed as:

$\dfrac{N_2}{N_1} = e ^{^{-\dfrac{(E_2-E_1)}{KT}}} = e ^{^{-\dfrac{(\Delta E)}{KT}}}$

From the above equation:

Δ E = energy difference = 3.13 × 10⁻¹⁸ J

k = Boltzmann constant = 1.38 × 10⁻²³ J/K

$\dfrac{N_2}{N_1} = 0.5$

Thus:

$0.05 =e^{^{ -\dfrac{3.13 \times 10^{-18} \ J}{1.38\times 10^{-23 \ J/K}\times T}}}$

$In (0.05) = { -\dfrac{3.13 \times 10^{-18} \ J}{1.38\times 10^{-23 \ J/K}\times T}}}$

$-3.00 = { -\dfrac{3.13 \times 10^{-18} \ J}{1.38\times 10^{-23 \ J/K}\times T}}}$

$-3.00 = -226811.5942 \times \dfrac{1}{T}$

$T = \dfrac{-226811.5942}{-3.00 }$

T = 75603.86473 K

4 0

3 years ago

What is a sensory neuron?

ASHA 777 [7]

Answer: Nerve cells within the nervous system that are in charge of converting external stimuli from the organism's environment into internal electrical impulses.

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3 years ago

A 10.00 g sample of a soluble barium salt is treated with an excess of sodium sulfate to precipitate 11.21 g BaSO4 (M- 233.4). W

aliina [53]

Answer:

The salt is barium chloride.

Explanation:

$BaX_2++Na_2SO_4\rightarrow BaSO_4+2NaX$