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3 years ago

The formula for sulfuric acid is H2SO4. A mole of sulfuric acid would have a mass of ___ grams.

Chemistry

1 answer:

pentagon [3]3 years ago

7 0

Answer:

98.0795 g

Explanation:

The molar mass of sulfuric acid is 98.0795 g/mol . This means that every mole of sulfuric acid has a mass of 98.0795 g.

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1. Currently, California students are in class 240 minutes every day. How many hours is this?

sweet [91]

Answer:

4 hours a day

Explanation:

240/60=4

3 0

3 years ago

Read 2 more answers

Determine the maximum amount of Fe that was produced during the experiment. Explain how you determined this amount.

dsp73

Answer:

5 moles of Fe

Explanation:

The equation of the reaction is;

2 Al(s) + Fe 2O 3(s) --> 2Fe (s) + Al 2O 3 (s)

Now;

1 mole of Fe2O3 require 2 moles of Al

3 moles of Fe2O3 requires 3 × 2/1 = 6 moles of Al

Hence Al is the limiting reactant.

If 2 moles of Al yields 2 moles of Fe

5 moles of Al yields 5 × 2/2 = 5 moles of Fe

5 0

3 years ago

The radius of an atom is dependent upon which 2 things? (Two answers)

matrenka [14]

Answer:

The correct options are;

C. The magnitude of attraction from its nucleus

D. The distance between the electrons and its nucleus

Explanation:

The atomic radius reduces, within a given period, as we move from left to right, the number of protons increases alongside the number of electrons and the while the quantum shell to which the extra electrons are added to is the same. Therefore, the radius of the atom is dependent on the magnitude of the attraction from the nucleus

Similarly, as we progress to the next period, with an extra quantum shell, the atomic radius is seen to increase.

Therefore, the atomic radius is determined by the distance between the electrons and its nucleus.

6 0

3 years ago

Can someone help me please and please show work

FinnZ [79.3K]

Answer:

Average of the trial is: 288.50 C

Percent Error: 3.83%

Explanation:

(291 + 287 + 295 + 281) : 4 = 288.50 C

Average: 288.50 C

Percent Error: {(300 - 288.50) : 300} x 100% = 3.83 %

4 0

3 years ago

A compound is 7.74% hydrogen and 92.26% carbon by mass. At 100°C a 0.6883 g sample of the gas occupies 250 mL when the pressure

ycow [4]

Answer: The molecular formula for the compound is $C_6H_6$

Explanation:

We are given:

Percentage of C = 92.26 %

Percentage of H = 7.74 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 92.26 g

Mass of H = 7.74 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{92.26g}{12g/mole}=7.68moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{7.74g}{1g/mole}=7.74moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 7.68 moles.

For Carbon = $\frac{7.68}{7.68}=1$

For Hydrogen = $\frac{7.74}{7.68}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is $CH$

Calculating the molar mass of the compound:

To calculate the molecular mass, we use the equation given by ideal gas equation:

PV = nRT

Or,

$PV=\frac{m}{M}RT$

where,

P = pressure of the gas = 820 torr

V = Volume of gas = 250 mL = 0.250 L (Conversion factor: 1 L = 1000 mL )

m = mass of gas = 0.6883 g

M = Molar mass of gas = ?

R = Gas constant = $62.3637\text{ L. torr }mol^{-1}K^{-1}$

T = temperature of the gas = $100^oC=(100+273)K=373K$

Putting values in above equation, we get:

$820torr\times 0.250L=\frac{0.6883g}{M}\times 62.3637\text{ L torr }mol^{-1}K^{-1}\times 373K\\\\M=\frac{0.6883\times 62.3637\times 373}{820\times 0.250}=78.10g/mol$