One side drops into fault
If T=const
P1V1=P2V2
P1*4L=P2*1L
P2=4P1
pressure increases by factor of 4
To find mass we use the formula Mass = moles x RFM: Mass = 0.560 x 180 = 100.8g of C₉H₈O₄
Hope that helps :)
In the data, 0.20 ppm is an outlier and this can be rejected if there is a 95% confidence level.
<h3>What is an outlier?</h3>
When analyzing data an outlier is a value that is abnormal or too different from other data. In the case presented 0.20 can be tagged as an outlier because other values such as 0.11, 0.12, 0.13, and 0.14 are similar while 0.20 is outside this range.
<h3>Should this piece of data be rejected?</h3>
The general rule is that if there is a 95% of confidence or higher you can reject an outlier, knowing the other data occurs 95% of the time, and therefore the outlier is improbable.
Based on this, you can reject an outlier if the confidence level is 95%.
Learn more about outlier in: brainly.com/question/9933184
Data Given:
Initial Volume = V₁ = 36.7 L
Initial Pressure = P₁ = 145 kPa
Initial Temperature = T₁ = 65 °C + 273 = 338 K
Final Volume = V₂ = ?
Final Pressure = P₂ = 101.325 kPa (Standard Pressure)
Final Temperature = T₂ = 273 K (Standard Temperature)
Formula used:
As number of moles are constant, so Ideal Gas equation in following form is used,
P₁ V₁ / T₁ = P₂ V₂ / T₂
Solving for V₂,
V₂ = P₁ V₁ T₂ / T₁ P₂
Putting Values,
V₂ = (145 kPa × 36.7 L × 338 K) ÷ (273 K × 101.325 kPa)
V₂ = 1798667 ÷ 27661.25
V₂ = 65.02 L
