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Vladimir79 [104]
3 years ago
13

A weight lifter lifts a 345 N set of weights from ground level to a position over his head, a vertical distance of 1.89 m. How m

uch work does the weight lifter do, assuming he moves the weights at constant speed?
Physics
1 answer:
Pavlova-9 [17]3 years ago
3 0

Answer:652.05 J

Explanation:

Given

Weight of lifter W=345 N

vertical distance move h=1.89 m

Work done in lifting the weight is equal change in Potential Energy of weight

Change in Potential Energy =m g h

\Delta PE=345 \times 1.89=652.05 J

therefore work done is equal to 652.05 J  

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Does red or green light have more energy.
dalvyx [7]

Answer: Green Light

Explanation:

The color green has a higher frequency than the color red and the higher the frequency the more energy. If you looks at a rainbow you'll see red on one end and violet on the other. Red has the least energy Violet has the most.

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Recommend An architect wants to design a conference room that
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Answer:

Install sound absorbers such as foam or acoustical panels

Explanation:

They could install some sound absorbers such as foam or acoustical panels in the walls, floors, and ceiling of the conference room.

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3 years ago
A 0.37-kg object connected to a light spring with a force constant of 23.2 N/m oscillates on a frictionless horizontal surface.
mars1129 [50]

Answer:

a) v = 31.67 cm / s , b)   v = -29.36 cm / s , c) v= 29.36 cm/s, d) x = 3.46 cm

Explanation:

The angular velocity in a simple harmonic movement is

       w = √ K / m

       w = √ 23.2 / 0.37

       w = 7,918 rad / s

a) the expression against the movement is

        x = A cos (wt + Ф)

Speed ​​is

        v = dx / dt = - A w sin (wt + Ф)

 The maximum speed occurs for cos = ± 1

        v = A w

        v = 4.0 7,918

        v = 31.67 cm / s

b) as the object is released from rest

        0 = -A w sin (0+ Фi)

        sin Ф = 0

         Ф = 0

The equation is

        x = 4.0 cos (7,918 t)

        v = -4.0 7,918 sin (7,918 t)

        v = - 31.67 sin (7.918t)

     

Let's look for the time for a displacement of x = 1.5 cm, remember that the angles must be in radians

          7,918 t = cos⁻¹ 1.5 / 4.0

          t = 1,186 / 7,918

          t = 0.1498 s

We look for speed

         v = -31.67 sin (7,918 0.1498)

         v = -29.36 cm / s

c) if the object passes the equilibrium equilibrium position again at this point the velocity has the same module, but the opposite sign

         v = 29.36 cm / s

d) let's look for the time for the condition v = v_max / 2

         31.67 / 2 = 31.67 sin ( 7,918 t)

          7.918t = sin⁻¹ 0.5

         t = 0.5236 / 7.918

         t = 0.06613

With this time let's look for displacement

         x = 4.0 cos (7,918 0.06613)

        x = 3.46 cm

6 0
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Two objects, Object A and Object B, need to be identified. Object A's index of refraction is determined to be 1.77, and Object B
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The correct answer is

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In fact, the index of refraction of a material is defined as:

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v=\frac{c}{n}

So we that, the smaller the refractive index n, the greater the speed of light in the material, v. In this problem, object B has lower refractive index than object A, so light travels faster in object B.

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