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Dovator [93]
3 years ago
12

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics

, you ask one of the archers to shoot an arrow parallel to the ground. You find the arrow stuck in the ground 52.0 away, making a 3.00 angle with the ground.
How fast was the arrow shot in m/s?
Physics
1 answer:
valentina_108 [34]3 years ago
3 0

Answer:

v = 69.82 ms^-1

Explanation:

As we know,

R = vi2 sin2Ꝋ / g  

vi2 =R g / sin2 Ꝋ where R is range R = 52m, Ꝋ = 3 Degrees

vi2 = 52 x 9.8 / sin 2(3) = 4875.227

v = 69.82 ms^-1

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Explanation:

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P(t) = (9.20*cos(69°)*t, -4.9m/s^2*t^2 + 9.20m/s^2*sin(69°)*t)

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h =  -4.9m/s^2*(1.28s)^2 + 9.20m/s^2*sin(69°)*1.28s = 2.96m

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