This question is asking the force on the rope. We can find this by using centripetal acceleration, then multiply by the ice skater's mass.
First we need to find the centripetal acceleration, which is a = v^2/r
We are given v and r, so we solve for a.
a = [(5.14m/s)^2]/(0.525m) = 50.323 m/s^2
Next multiply by the ice skater's mass (because F=ma) which is 44.6 kg
We then get F = (50.323m/s^2)(44.6kg) = 2244.407924N
Divide by 10^3 to get kN, we get:
2.244kN
Hope this helps!
Answer:
is there any pictures or diagrams that i could use to base this question off of
Explanation:
Answer:
t=0.417s
Explanation:
After the ball hits the racket it is in freefall(assume air resistance as negligible)
so a=-g
use
x-x0=v0t+1/2at^2
Plug in givens
20=50t-4.9t^2
Solve quadratic equation using quadratic formula
t= 0.417 seconds, (the other answer is extraneous because it is too big because in 1 second, the ball travels 50 meters)
Calculation of moisture content. Calculate the moisture content on a wet-weight basis using the following formula: Moisture content (%) = W2 - W3 x 100 W2-W1. where, W1 = weight of container with lid; W2 = weight of container with lid and sample before drying; and W3 = weight of container with lid and sample after drying.
