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vlabodo [156]
3 years ago
10

A stone fell from the top of a cliff into the ocean. In the air, it had an average speed of 161616 \text{m/s}m/sstart text, m, s

lash, s, end text. In the water, it had an average speed of 333 \text{m/s}m/sstart text, m, slash, s, end text before hitting the seabed. The total distance from the top of the cliff to the seabed is 127127127 meters, and the stone's entire fall took 121212 seconds.
Physics
2 answers:
givi [52]3 years ago
6 0

Answer: It takes the stone 7seconds in air and 5seconds in water

Explanation: complete question: How long did the stone fall in air and how long did it fall in the water?

total distance = sum of velocity * time for both legs of the journey;

let the time taken in air be t

hence time taken in water is 12-t

127 = 16*t + 3(12-t)

127 = 16t + 36 - 3t

127 - 36 = 16t - 3t

91 = 13t

t = 91/13 = 7 seconds 

Hence time taken in air = 7 seconds

time taken in water is 12 - 7 = 5 seconds

 

Vladimir [108]3 years ago
6 0

Answer:

The time it takes to travel in air is 7 seconds

The distance it travels in air is 112 m

The time it takes to travel in water is 5 seconds

The distance it travels in water is 15 m

Explanation:

Let t (s) be the time it takes for the stone to fall in the air. Since the total time is 12 s, then 12 - t is the time it takes to fall in the ocean before hitting the seabed.

The distance it would travel in air in t seconds at the rate of 16 m/s is 16t

The distance it would travel in water in 12 - t seconds at the rate of 3m/s is 3(12-t) = 36 - 3t

The total distance from the cliff to the seabed is 127m, which is 16t + 36 - 3t = 36 + 13t = 127

13t = 127 - 36 = 91

t - 91 / 13 = 7 seconds

The time it takes to travel in air is 7 seconds

The distance it travels in air is 7*16 = 112 m

The time it takes to travel in water is 12 - 7 = 5 seconds

The distance it travels in water is 5*3 = 15 m

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rosijanka [135]

Answer:

a

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b

      l = 37.13 \ LY

Explanation:

From the question we are told that

    The  speed of the spaceship is  v  =  0.800c

    Here  c is the speed of light with value  c =  3.0*10^{8} \ m/s

    The  length is  l = 31.2 \  m

     The  distance of the star for earth is d = 145 \  light \  years

     The  speed is v_s = 2.90 *10^{8}

     

Generally the from the length contraction equation we have that

       l  =  l_o  \sqrt{1 -[\frac{v}{c } ]}

Now the when at rest the length is  l_o

So  

      l_o =\frac{l}{\sqrt{ 1 - \frac{v^2}{c^2 } } }

      l_o =\frac{ 31.2 }{ \sqrt{1 - \frac{(0.800c ) ^2}{c^2} } }

      l_o=52 \  m

Considering b  

  Applying above equation

            l  =l_o \sqrt{1 -  [\frac{v}{c } ]}

Here l_o  =145 \  LY(light \ years )

So

           l=145 *  \sqrt{1 -  \frac{v_s^2}{c^2 } }

            l =145 *  \sqrt{ 1 - \frac{2.9 *10^{8}}{3.0*10^{8}} }

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3 years ago
What kind of surface is suitable for infared radiation
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Answer:

Different surfaces

<h3>You can see that dull surfaces are good absorbers and emitters of infrared radiation. Shiny surfaces are poor absorbers and emitters (but they are good reflectors of infrared radiation</h3>
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3 years ago
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saveliy_v [14]
If f=140hz
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4 0
3 years ago
A sled of mass 2.12 kg has an initial speed of 5.49 m/s across a horizontal surface. The coefficient of kinetic friction between
Darya [45]

Answer:

The speed of the sled is 3.56 m/s

Explanation:

Given that,

Mass = 2.12 kg

Initial speed = 5.49 m/s

Coefficient of kinetic friction = 0.229

Distance = 3.89 m

We need to calculate the acceleration of sled

Using formula of acceleration

a = \dfrac{F}{m}

Where, F = frictional force

m = mass

Put the value into the formula

a=\dfrac{\mu mg}{m}

a=\mu g

a=0.229\times9.8

a=2.244\ m/s^2

We need to calculate the speed of the sled

Using equation of motion

v^2=u^2-2as

Where, v = final velocity

u = initial velocity

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Put the value in the equation

v ^2=(5.49)^2-2\times2.244\times3.89

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v=3.56\ m/s

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8 0
3 years ago
Given the following specific heat capacities, which material was have the largest change in temperature if 10 grams of each subs
Ilya [14]

Answer:

Explanation:

Comment

You could calculate it out by assuming the same starting temperature for each substance. (You have to assume that the substances do start at the same temperature anyway).

That's like shooting 12 with 2 dice. It can be done, but aiming for a more common number is a better idea.

Same with this question.

You should just develop a rule.  The rule will look like this

The greater the heat capacity the (higher or lower) the change in temperature.

The greater the heat capacity the lower the change in temperature

That's not your question. You want to know which substance will have the greatest temperature change given their heat capacities.

Answer

lead. It has the smallest heat capacity and therefore it's temperature change will be the greatest.

5 0
1 year ago
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