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fenix001 [56]
3 years ago
9

You lay a mirror flat on the floor with one edge against a wall and aim a laser at the mirror. The ray reflects from the mirror

and strikes the wall. The plane of the incident and reflected rays is perpendicular to the wall. The ray from the laser strikes the mirror 22.7 cm from the wall, and the reflected ray strikes the wall 35.5 cm above the mirror. Find the angle of incidence of the laser ray on the mirror.
Physics
2 answers:
koban [17]3 years ago
6 0

Answer:

32.6°

Explanation:

Thinking process:

The angle of incidence is measured from the normal. The normal is a perpendicular line that is imaginary.

Thus, the right angle approach is used:

We know that:

tan\theta = \frac{opposite}{adjacent}  \\tan (angle of incidence) = \frac{22.7}{35.5} \\\theta = tan^{-1}( \frac{22.7}{35.5})\\                                                                                       = 32.6

Thus, the angle is = 32.6°

RideAnS [48]3 years ago
5 0

Answer:

  About 32.6°

Explanation:

The tangent of the desired angle is the ratio of distance from the wall to height up the wall:

  tan(angle of incidence) = (22.7 cm)/(35.5 cm) ≈ 0.63944

  angle of incidence = arctan(0.63944) ≈ 32.6°

_____

The angle of incidence is measured from the normal to the mirror.

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Answer : The volume of engine in cubic inches is, 427.166\text{ inch}^3

Explanation :

As we are given that the volume of engine is, 7.0 liters. Now we have to calculate the volume of engine in cubic inches.

Conversion used :

1\text{ liter}=1000cm^3

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or,

1cm=\frac{1}{2.54}\text{ inch}

1cm^3=(\frac{1}{2.54}\text{ inch})^3

As,

1cm^3=(\frac{1}{2.54}\text{ inch})^3

So,

7000cm^3=\frac{7000cm^3}{1cm^3}\times (\frac{1}{2.54}\text{ inch})^3=427.166\text{ inch}^3

Thu, the volume of engine in cubic inches is, 427.166\text{ inch}^3

3 0
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Help with 5 and the question below. BRAINLIEST FOR THE CORRECT ANSWER! Urgent Physics help!
krok68 [10]

Sound level at distance of 15 m is given as 20 dB

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now we know that

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