1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ahrayia [7]
3 years ago
5

Walls made of paraffin wax, a covalent compound, help keep the temperature in a room steady as night changes into day and day in

to night. What is the most important property of covalent compounds that allows paraffin wax to help keep a room’s temperature level? The wall would not absorb or release any heat energy from the room or outside, so it would not affect the room’s temperature. The wall would not absorb heat during the day, but at night it would release heat that naturally exists inside of most covalent compounds. The wall would absorb extra heat during the day when the sun is out, then release the heat back into the room when the sun goes down. The wall would absorb extra heat during the day, and the wall would hold this heat in so that it cannot absorb any more heat from the night air.
Chemistry
2 answers:
Over [174]3 years ago
8 0
The wall would absorb extra heat during the day when the sun is out, then release the heat back into the room when the sun goes down.
MAXImum [283]3 years ago
7 0

Answer: Option (c) is the correct answer.

Explanation:

Covalent compounds are the compounds in which atoms combine by sharing of electrons.

These compounds have weak forces of attraction and therefore, they easily heat up and thus, have low melting and boiling point.

Hence, the most important property of covalent compounds that allows paraffin wax to help keep a room’s temperature level is that the wall would absorb extra heat during the day when the sun is out, then release the heat back into the room when the sun goes down.

You might be interested in
I NEED THIS NOW PLEASE HELP ​
ad-work [718]

Answer:

photosynthesis

Explanation:

its the first step of the cycle

3 0
4 years ago
You need to produce a buffer solution that has a pH of 5.26. You already have a solution that contains 10. mmol (millimoles) of
Andreas93 [3]

The question is incomplete, complete question is :

You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? The pka of acetic acid is 4.74.

Answer:

33.11 millimoles of acetate we will need to add to this solution.

Explanation:

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[salt]}{[acid]})

Where :

tex]pK_a[/tex] = negative logarithm of acid dissociation constant of acid

[salt] = Concentration of salt

[Acid] = Concentration of salt

We have:

pH = 5.26

pK_a=4.74

[salt] =[CH_3COO^-] = ?

[acid] = [CH_3COOH]=10.0 mmol

5.26=4.74+\log(\frac{[CH_3COO^-]}{[10.0 mmol]})

[CH_3COO^-]=33.11 mmol

33.11 millimoles of acetate we will need to add to this solution.

3 0
4 years ago
6) How many valence electrons does an atom of Cu possess?
agasfer [191]
The answer is c)11 because copper has 11 valence electrons
7 0
3 years ago
John dissolves .5g of a white powder in 25g of benzene (FP 5oC) (kf benzene is 5.1) and finds the solution freezes at 3.7oC. Det
navik [9.2K]

Answer:

The compound has a molar mass of 78.4 g/mol

Explanation:

Step 1: data given

Mass of a sample = 0.5 grams

Mass of benzene = 25 grams

Freezing poing = 5 °C

Kf of benzene = 5.1 °C/m

Freezing point solution = 3.7 °C

Step 2: Calculate molality

ΔT = i*Kf*m

⇒with ΔT = the freezing point depression = 5.0 - 3.7 = 1.3 °C

⇒with i = the can't hoff factor = 1

⇒with Kf = the freezing point depression constant of benzene = 5.1 °C/m

⇒with m = the molality

1.3 = 5.1 * m

m = 1.3 / 5.1

m = 0.255 moles /kg

Step 3: Calculate moles

Molality = moles / mass benzene

0.255 molal = moles / 0.025 kg

Moles = 0.255 molal * 0.025 kg

Moles = 0.006375 moles

Step 4: Calculate molar mass of the compound

Molar mass compund = mass / moles

Molar mass compound = 0.5 grams / 0.006375 moles

Molar mass compound = 78.4 g/mol

The compound has a molar mass of 78.4 g/mol

7 0
3 years ago
if the piece of paper is cut in half over and over again, will there ever be a point at which it is no longer paper? explain you
Alisiya [41]

Answer:

No, cutting paper is a physical change. Meaning that it is still paper no matter how many times you cut it. its chemical properties have not changed and it is still paper. cutting it would just give you smaller pieces of paper.

4 0
4 years ago
Other questions:
  • Which of the following is equal to 2.0 liters? 200 mL 2,000 cm3 20 m3 20,000 mm3
    14·1 answer
  • When hydronium and hydroxide neutralize each other as they react in equal amounts, what is true of their molarities? A. Their mo
    9·2 answers
  • Question 25 a chemist determined by measurements that 0.020 moles of mercury participated in a chemical reaction. calculate the
    6·1 answer
  • In a reaction, NH3, yields NH4+"
    13·1 answer
  • 5. How many atoms of hydrogen are in a molecule of acetic acid (HC2H202)?
    6·1 answer
  • I need to know how to solve the equations.​
    6·1 answer
  • What does the ozone do for us? As in us humans?
    8·2 answers
  • A saturated hydrocarbon having molecular formula CnH2n+2 diffuses through a porous membrane twice as fast as sulphur dioxide. Ca
    12·1 answer
  • Is this tinder like my guy
    9·1 answer
  • Injury to brain is fatal. So brain is protected from external shock and injury. State the ways brain is protected in the body.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!