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ahrayia [7]
3 years ago
5

Walls made of paraffin wax, a covalent compound, help keep the temperature in a room steady as night changes into day and day in

to night. What is the most important property of covalent compounds that allows paraffin wax to help keep a room’s temperature level? The wall would not absorb or release any heat energy from the room or outside, so it would not affect the room’s temperature. The wall would not absorb heat during the day, but at night it would release heat that naturally exists inside of most covalent compounds. The wall would absorb extra heat during the day when the sun is out, then release the heat back into the room when the sun goes down. The wall would absorb extra heat during the day, and the wall would hold this heat in so that it cannot absorb any more heat from the night air.
Chemistry
2 answers:
Over [174]3 years ago
8 0
The wall would absorb extra heat during the day when the sun is out, then release the heat back into the room when the sun goes down.
MAXImum [283]3 years ago
7 0

Answer: Option (c) is the correct answer.

Explanation:

Covalent compounds are the compounds in which atoms combine by sharing of electrons.

These compounds have weak forces of attraction and therefore, they easily heat up and thus, have low melting and boiling point.

Hence, the most important property of covalent compounds that allows paraffin wax to help keep a room’s temperature level is that the wall would absorb extra heat during the day when the sun is out, then release the heat back into the room when the sun goes down.

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Is centigrams or grams bigger.<br> example: which unit is larger.<br> 35cg or 35 g
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Answer:

35g

Explanation:

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3 years ago
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If the visible light spectrum is from 400 to 700 nm, would light with an energy of 2.79 x 10^-19 J be visible with the naked eye
sladkih [1.3K]

Answer:

713 nm. It is not visible with the naked eye.

Explanation:

Step 1: Given data

  • Energy of light (E): 2.79 × 10⁻¹⁹ J
  • Planck's constant (h): 6.63 × 10⁻³⁴ J.s
  • Speed of light (c): 3.00 × 10⁸ m/s
  • Wavelength (λ): ?

Step 2: Calculate the wavelength of the light

We will use the Planck-Einstein equation.

E = h × c / λ

λ = h × c / E

λ = 6.63 × 10⁻³⁴ J.s × 3.00 × 10⁸ m/s / 2.79 × 10⁻¹⁹ J

λ = 7.13 × 10⁻⁷ m

Step 3: Convert "λ" to nm

We will use the relationship 1 m = 10⁹ nm.

7.13 × 10⁻⁷ m × (10⁹ nm/1 m) = 713 nm

This light is not in the 400-700 nm interval so it is not visible with the naked eye.

5 0
3 years ago
The Earth's mantle is
EleoNora [17]

Answer:

C. cooler than both the crust and the core

Explanation:

It is observed that at the mantle, temperatures range from estimatedly 200 °C (392 °F) around the upper boundary with the crust to approximately 4,000 °C (7,230 °F) at the core-mantle boundary.

So we can say the mantle is cooler than both the crust and the core.

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3 years ago
All organelles need energy to function which cell organelle provides the energy?
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6 0
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it takes 463 kJ/mol to break an oxygen-hydrogen single bond. calculate the maximum wavelength of light for which an oxygen-hydro
Marianna [84]

Answer:

  • <u>2.59 × 10⁻⁷ m  = 259 nm</u>

Explanation:

You need to calculate the wavelength of a photon with an energy equal to 463 kJ/mol, which is the energy to break an oxygen-hydrogen atom.

The energy of a photon and its wavelength are related by the Planck - Einstein equation:

  • E = hν,

Where:

  • E = energy of a photon,
  • h = Planck constant (6.626 × 10⁻³⁴ J . s) and
  • ν = frequency of the photon.

And:

  • ν = c / λ

Where:

  • c = speed of light (3.00 × 10⁸ m/s in vacuum)
  • λ = wavelength of the photon

Thus, you can derive:

  • E = h c / λ

Solve for λ:

  • λ = h c / E

Before substituting the values, convert the energy, 463 kJ/ mol, to J/bond

  • 463 kJ/ mol × 1,000 J/kJ × 1 mol / 6.022 × 10 ²³ atom × 1 bond / atom

       = 7.69×10²³ J / bond

Substitute the values and use the energy of one bond:

  • λ = 6.626 × 10⁻³⁴ J . s × 3.00 × 10⁸ m/s / 7.69×10²³ J = 2.59 × 10⁻⁷ m

The wavelength of light is usually shown in nanometers:

  • 2.59 × 10⁻⁷ m × 10⁹ nm / m = 259 nm ← answer
6 0
3 years ago
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