All categories

3 years ago

Which of these statements about enzymes is true?

1 answer:

7 0

Enzymes are organic catalysts
and catalysts generally increase rate of reaction by lowering activation energy
C is the answer

You might be interested in

i need help im a dum bleep who kept talking to guys on dc and one wont leave me alone what do i do (▰˘◡˘▰) (i already blocked hi

Andrew [12]

Answer:

Delete your discord acc, and make another one. Prob should change email tbh. If he keeps doing it you can report him, because it's like online stalking.

Explanation:

6 0

3 years ago

Calculate the solubility of copper(II) hydroxide, Cu(OH)2, in g/L

Oduvanchick [21]

Answer:

Ksp = [ Cu+² ] [ OH-] ²

molar mass Cu(oH )2 ==> M= 63.546 (1) + 16 (2) + 1 (2) = 97.546 g/mol

Ksp = [ Cu+² ] [ OH-] ²

Ksp [ cu (OH)2 ] = 2.2 × 10-²⁰

|__________|___Cu+² __|_2OH-____|

|Initial concentration(M)|___0__|_0______|

|Change in concentration(M)|_+S |__+2S__|

|Equilibrium concentration(M)|_S _|2S___|

Ksp = [ Cu+² ] [ OH-] ²

2.2 ×10-²⁰ = (S)(2S)²= 4S³

$s = \sqrt[3]{ \frac{2.2 \times {10}^{ - 20} }{4} } = 1.8 \times {10}^{ - 7}$

S = 1.8 × 10-⁷ M

The molar solubility of Cu(OH)2 is 1.8 × 10-⁷ M

Solubility of Cu (OH)2 =

$Cu (OH)2 = \frac{1.8 \times {10}^{ - 7} mol \:Cu (OH)2 }{1L} \times \frac{97.546 \: g \: Cu (OH)2}{1 \: mol \: Cu (OH)2} \\ = 1.75428 \times 10 ^{ - 5}$

<h3>Solubility of Cu (OH)2 = 1.75428 × 10 -⁵ g/ L</h3>

I hope I helped you^_^

8 0

2 years ago

What the branch of a zoologist

MrRa [10]

The branch of biology that deals with animals and animal life, including the study of the structure, physiology, development, and classification of animals. The animal life of a particular area or period: the zoology of Alaska; the zoology of the Pleistocene.

6 0

3 years ago

Read 2 more answers

A particular first-order reaction has a rate constant of 1.35 × 102 s-1 at 25.0°C. What is the magnitude of k at 95.0°C if Ea =

never [62]

Answer:

k ≈ 9,56x10³ s⁻¹

Explanation:

It is possible to solve this question using Arrhenius formula:

$ln\frac{k2}{k1} = \frac{-Ea}{R} (\frac{1}{T2} -\frac{1}{T1} )$

Where:

k1: 1,35x10² s⁻¹

T1: 25,0°C + 273,15 = 298,15K

Ea = 55,5 kJ/mol

R = 8,314472x10⁻³ kJ/molK

k2 : ???

T2: 95,0°C+ 273,15K = 368,15K

Solving:

$ln\frac{k2}{k1} = 4,257$

$\frac{k2}{k1} = 70,593$

${k2} = 9,53x10^3 s^{-1}$

k ≈ 9,56x10³ s⁻¹

I hope it helps!

5 0

2 years ago

Are properties such as odor, color, density, and solubility physical or chemical properties?

storchak [24]

Physical properties- color, density, solubility.
Chemical property- odor.

You see, a physical property is any property that can be measured , and a one that describes the state of the physical system.

https://socratic.org/questions/are-properties-such-as-odor-color-density-and-solubility-physical-or-...

8 0

3 years ago

Read 2 more answers