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Reika [66]
3 years ago
15

Magnesium has three stable isotopes. The most commonly occurring isotope, 24 Mg, has an isotopic mass of 23.985 u and makes up 7

8.99 % of naturally occurring magnesium atoms. The isotope 25 Mg makes up 10.00 % of magnesium atoms and has an isotopic mass of 24.986u. The isotope 26 Mg makes up 11.01 % of magnesium atoms and has an isotopic mass of 25.983 u. Using the isotopic composition provided, calculate the average atomic mass of magnesium.
Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
4 0

Answer:

Average atomic mass = 24.3051 amu

Explanation:

Average Atomic Mass = (Mass of Isotope 1 x Fractional Abundance of Isotope 1) + (Mass of Isotope 2 x Fractional Abundance of Isotope 2) + ......

For 24 Mg

Mass = 23.985 amu

Fractional Abundance = 0.7899

Mass * Fractional Abundance = 18.9458

For 25 Mg

Mass = 24.986 amu

Fractional Abundance = 0.10

Mass * Fractional Abundance = 2.4986

For  26 Mg

Mass = 25.983

Fractional Abundance = 0.1101

Mass * Fractional Abundance = 2.8607

Average atomic mass = 24 Mg + 25 Mg + 26 Mg

Average atomic mass = 18.9458 + 2.4986 + 2.8607

Average atomic mass = 24.3051 amu

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7 0
2 years ago
Read 2 more answers
1. You are asked to make 200 mls of a 20mM working (diluted) solution of NaCl using a 2M stock solution. Record the volume of 2M
vekshin1

Answer:

The volume of 2M stock solution added = 2 mL

The volume of water = 198 mL

Explanation:

Considering

Molarity_{working\ solution}\times Volume_{working\ solution}=Molarity_{stock\ solution}\times Volume_{stock\ solution}

Given  that:

Molarity_{working\ solution}=20\ mM=0.02\ M

Volume_{working\ solution}=200\ mL

Volume_{stock\ solution}=?

Molarity_{stock\ solution}=2\ M

So,  

0.02\ M\times 200\ mL=2\ M\times Volume_{stock\ solution}

Volume_{stock\ solution}=\frac{0.02\times 200}{2}\ mL=2\ mL

<u>The volume of 2M stock solution added = 2 mL</u>

<u>The volume of water = 200 - 2 mL = 198 mL</u>

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3 years ago
How many microliters of original sample are required to produce a final dilution of 10-2 in a total volume of 0.2 mL? 1 microlit
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Answer:

The required volume of the original sample required is 2 micro liter

Explanation:

assuming the original sample concentration is 1N

after  final dilution of 10-2 solution concentration becomes 0.01 N

normality of original sample  = 1 N

normality  of final solution = 0.01 N

volume of  original sample= ?

volume of   final solution  = 0.2 mL

Considering thef formula below :

N1V1 = N2V2

V1 = (N2V2)/N1

= (0.01*0.2)/1

= 0.002 mL

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The original sample required is 2 micro liter

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4 years ago
The element found naturally in the earth that has the heights atomic number is
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The element found naturally in the earth , that has the highest atomic number is 7

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