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Katarina [22]
3 years ago
8

A geologist is studying rock layers in an old river bed, and he finds a fossil of a fish and a horsetail rush in the same rock l

ayer. According to the law of faunal and floral succession, the geologist can assume that the rock containing the fossils may date back as far as the _____.
Cambrian period
Ordovician period
Silurian period
Devonian period

Physics
2 answers:
erastovalidia [21]3 years ago
8 0

The correct answer is Devonian period.

This is known to be the period of fishes which occurred 416 million years ago. It is known to be the fourth period of the Paleozoic Era. Significant events like evolution of first insects and other animals.

The Fishes evolved in the Ordovician era but the horses were found in the Devonian period only.

KonstantinChe [14]3 years ago
6 0
A geologist is studying rock layers in an old river bed, and he finds a fossil of a fish and a horsetail rush in the same rock layer. According to the law of faunal and floral succession, the geologist can assume that the rock containing the fossils may date back as far as the <span>Devonian period</span>.
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After an initial test run John determines that his cooling system generates 45 W of heat loss. Calculate the amount of heat loss
anyanavicka [17]

Given:

heat generated by John's cooling system,  H = \rho A v^{3}  = 45 W    (1)

If ρ, A, and v corresponds to John's cooling system then let \rho_{1}, A_{1}, v_{1} be the variables for Mike's system then:

\rho  = 9.5\rho_{1}

\rho_{1}  = \frac{\rho}{9.5}

v_{1} =3.5 v

Formula use:

Heat generated, H = \rho A v^{3}

where,

\rho = density

A = area

v = velocity

Solution:

for Mike's cooling system:

H_{2} = v_{1}^{3}{1}A_{1}\rho_{1}

⇒ H_{2} = (3.5v)^{3} × A × \frac{\rho}{9.5}

H_{2} = 4.513v^{3} A  \rho

Using eqn (1) in the above eqn, we get:

H_{2} = 4.513 × 45 = 203.09 W

5 0
3 years ago
Clouds can weigh thousands of pounds due to their liquid water content. Often this content is measured in grams per cubic meter
-Dominant- [34]

Answer:

a) 0.2399 mi³

b) 440.8 × 10³ Pounds

Explanation:

Given:

Volume of cumulus cloud, V = 1 km³

Liquid water content = 0.2 g/m³

Now,

a) 1 km = \frac{\textup{1 miles}}{\textup{1.6093}}

thus,

1 km³ = (\frac{\textup{1 miles}}{\textup{1.6093}})^3

1 km³ =  0.2399 mi³

Hence, volume of cloud in cubic miles is 0.2399 mi³

b)

Liquid water content = 0.2 g/m³

Now,

1 Km = 1000 m

thus,

1 km³ = 1000³ m³

Therefore,

Liquid water content in 1 Km³ of cloud = 0.2 g/m³ × 1000³ m³

= 200 × 10⁶ gram

or

= 200 × 10³ Kg

also,

1 kilogram =  2.204 pounds

Therefore,

200 × 10³ Kg = 200 × 10³ × 2.204 pounds = 440.8 × 10³ Pounds

8 0
4 years ago
Dr. Evil stands on a 150 m high cliff and drops the kittens straight down. Fill out the following table that shows how the veloc
riadik2000 [5.3K]
I would say d if I remember right I think that’s what I put and got right sorry if it’s wrong
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3 years ago
To determine the focal length of a convex lens, a student focuses a classroom window, a
Reptile [31]

If we use the sun as a distant object to calculate the convex lens's focal length, we obtain a number that is more closely related to the actual convex lens value.

We need to learn more about a convex lens's focal length in order to locate the solution.

<h3>Why, if we concentrate the sun, do we obtain a focal length that is closer to the correct value?</h3>
  • An optical system's focal length is a measurement of how sharply the light converges or diverges.
  • The distance between the convex lens's pole and its focus is known as its focal length.
  • Convex lenses focus all of the rays from the distant object at their focal point to create a true image.
  • We receive a crisper image if the object is farther away from the lens.
  • Away from the focal point, an image will form if we concentrate on a neighboring window.
  • To get the focal point on a distant tree, we must move the screen in the direction of the lens.

We can therefore draw the conclusion that if we use the sun as a distant object, we will obtain a value that is closer to the convex lens's actual value.

Learn more about a convex lens's focal length here:

brainly.com/question/28039799

#SPJ1

7 0
2 years ago
Read 2 more answers
The specific heat of silver is 0.057 calories/gram°C. If 10.0 grams of silver were heated and the temperature of the sample chan
Triss [41]
Since the specific heat of silver is given to be 0.057 calories/gram*C, obtaining the amount of calories should be as easy as multiplying the specific heat by the given values of the weight and the temperature to do unit cancellation. This is shown below:

(<span>0.057 calories/gram*C</span>)(10 grams)(20 C) = 11.4 calories
6 0
4 years ago
Read 2 more answers
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