A horse pulls a barge along a canal using a rope 10m
1 answer:
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Answer:
3091.56
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s² (positive downward and negative upward)
Distance traveled in the first stage is 1093.75 m
Velocity at the end of first stage is 87.5 m/s
Acceleration of the second stage is 4.5 m/s²
Distance traveled in the second stage is 1100 m
Distance traveled after the second stage has stopped firing is 894.81 m
Total height the rocket reached = 1093.75+1100+897.81 = 3091.56 m
The distance covered by the proton is 48.4 m
Explanation:
The electric field produced by an electrically charged infinite plane is given by
where in this case,
is the surface charge density
is the vacuum permittivity
Substituting,
And the direction is towards the plane (because the charge is negative).
The electric force on the proton due to this field is
where
is the proton charge
Substituting,
where the direction is toward the plane.
Now we can calculate the proton's acceleration using Newton's second law:
where
is the proton mass
Substituting,
Now we can finally apply the following suvat equation for accelerated motion to find the distance travelled by the proton:
where
v = 0 is the final velocity
is the initial velocity
a is the acceleration
s is the distance covered
And solving for s,
Therefore, the closest answer is 48.4 m.
Learn more about accelerated motion:
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