All categories

4 years ago

Economics is the study of producing and ____ goods and services.

Physics

2 answers:

user100 [1]4 years ago

3 0

Economics is the study of producing and consuming goods and services.

Economics show the GDP, or Growth domestic product, which show if a country is making more and intaking less products compared too others. The higher the GDP, usually (unless consumption is great too), the more built up the country is.

hope this helps

Georgia [21]4 years ago

3 0

The correct answer is: consuming

This is the correct asnwer due to the fact that economics is a branch of social science that studies the production, distribution, and consumption of goods and services.

I hope this answer has helped you :)

You might be interested in

which planet should punch travel to if his goal is to weigh in at 118 lb? refer to the table of planetary masses and radii given

Harrizon [31]

The planet that Punch should travel to in order to weigh 118 lb is Pentune.

<h3 /><h3 /><h3>The given parameters:</h3>

Weight of Punch on Earth = 236 lb
Desired weight = 118 lb

The mass of Punch will be constant in every planet;

$W = mg\\\\m = \frac{W}{g}\\\\m = \frac{236}{g}$

The acceleration due to gravity of each planet with respect to Earth is calculated by using the following relationship;

$F = mg = \frac{GmM}{R^2} \\\\g = \frac{GM}{R^2}$

where;

M is the mass of Earth = 5.972 x 10²⁴ kg
R is the Radius of Earth = 6,371 km

For Planet Tehar;

$g_T =\frac{G \times 2.1M}{(0.8R)^2} \\\\g_T = 3.28(\frac{GM}{R^2} )\\\\g_T = 3.28 g$

For planet Loput:

$g_L =\frac{G \times 5.6M}{(1.7R)^2} \\\\g_L = 1.94(\frac{GM}{R^2} )\\\\g_L = 1.94g$

For planet Cremury:

$g_C =\frac{G \times 0.36M}{(0.3R)^2} \\\\g_C = 4(\frac{GM}{R^2} )\\\\g_C = 4 g$

For Planet Suven:

$g_s =\frac{G \times 12M}{(2.8R)^2} \\\\g_s = 1.53(\frac{GM}{R^2} )\\\\g_s = 1.53 g$

For Planet Pentune;

$g_P =\frac{G \times 8.3 }{(4.1R)^2} \\\\g_P = 0.5(\frac{GM}{R^2} )\\\\g_P = 0.5 g$

For Planet Rams;

$g_R =\frac{G \times 9.3M}{(4R)^2} \\\\g_R = 0.58(\frac{GM}{R^2} )\\\\g_R = 0.58 g$

The weight Punch on Each Planet at a constant mass is calculated as follows;

$W = mg\\\\W_T = mg_T\\\\W_T = \frac{236}{g} \times 3.28g = 774.08 \ lb\\\\W_L = \frac{236}{g} \times 1.94g =457.84 \ lb\\\\ W_C = \frac{236}{g}\times 4g = 944 \ lb \\\\ W_S = \frac{236}{g} \times 1.53g = 361.08 \ lb\\\\W_P = \frac{236}{g} \times 0.5 g = 118 \ lb\\\\W_R = \frac{236}{g} \times 0.58 g = 136.88 \ lb$

Thus, the planet that Punch should travel to in order to weigh 118 lb is Pentune.

<u>The </u><u>complete question</u><u> is below</u>:

Which planet should Punch travel to if his goal is to weigh in at 118 lb? Refer to the table of planetary masses and radii given to determine your answer.

Punch Taut is a down-on-his-luck heavyweight boxer. One day, he steps on the bathroom scale and "weighs in" at 236 lb. Unhappy with his recent bouts, Punch decides to go to a different planet where he would weigh in at 118 lb so that he can compete with the bantamweights who are not allowed to exceed 118 lb. His plan is to travel to Xobing, a newly discovered star with a planetary system. Here is a table listing the planets in that system (<em>find the image attached</em>).

<em>In the table, the mass and the radius of each planet are given in terms of the corresponding properties of the earth. For instance, Tehar has a mass equal to 2.1 earth masses and a radius equal to 0.80 earth radii.</em>

Learn more about effect of gravity on weight here: brainly.com/question/3908593

5 0

2 years ago

The force per meter between the two wires of a jumper cable being used to start a stalled car is 0.244 N/m. (a) What is the curr

MakcuM [25]

Answer: current I is 144amp(A)

Explanation: The force per lenght F/L, current l, and separation distance r are related by the formula

F/L = permeability of space* I²/2*pi*r

Permeability of free space is 1.257*EXP {-6} Henry/meter

F/L is 0.244 N/m, pi is 3.142,

r is 1.7cm which is equal to 0.017meter.

I is what we are looking for.

Now we have after substitution,

0.244

= 1.257*EXP {-6} * I²/(2*3.142*0.017)

After cross multiplying and making I² subject of formula we have,

0.0261/(1.257*EXP {-6}) = I²

I = √{20736.7} =144ampere(A)

That means in each of the jumper wire there is 144amp(A)

8 0

3 years ago

PLS HELP WILL GIVE 50 POINTS

gregori [183]

Answer:

I'm pretty sure its radiation and reflection. Some of the Sun's energy gets reflected off into space. (I could be wrong though)

8 0

3 years ago

Read 2 more answers

WHAT ARE 5 EXAMPLES of REAL science

zlopas [31]

Answer:

physics

kinematics

dynamics

fluid mechanisms

earth sciences

4 0

3 years ago

All objects emit electromagnetic radiation as a result of _____.

Artist 52 [7]

One

All objects, every one, as long as the object is not at absolute zero (not very many objects are -- like no common object) emit electromagnetic radiation because they possess thermal (heat) energy.

The answer, surprisingly, is A.

Two

This is just an example of Snells law. The angles are with the normal.

Index of Refraction = sin(input angle) / sin(outgoing angle)

Index of Refraction = sin(angle incidence)/sin(angle of refraction)

Index of Refraction = Sin (36)/Sin(27.5)

Index = 1.28 (rounded)

8 0

3 years ago