Question

Calculate the linear acceleration (in m/s2) of a car, the 0.330 m radius tires of which have an angular acceleration of 13.0 rad/s2. Assume no slippage. 4.29 Correct: Your answer is correct. m/s2 (b) How many revolutions do the tires make in 2.50 s if they start from rest? 13.4 Incorrect: Your answer is incorrect. rev (c) What is their final angular velocity (in rad/s)? 10.73 Incorrect: Your answer is incorrect. rad/s (d) What is the final velocity (in m/s) of the car? 4.42 Incorrect: Your answer is incorrect. m/s

Answer 1

Answer:

a) $a_t=4.29m/s^2$

b) $d=6.40rev$

c) $\omega=32.5rad/s$

d) $v=10.7m/s$

Explanation:

the linear acceleration is given by:

$a_t=r*\alpha\\a_t=0.330m*13.0rad/s^2\\a_t=4.29m/s^2$

for b)

$d=\frac{1}{2}\alpha*t^2\\d=\frac{1}{2}*13.0*(2.50)^2\\d=40.2rad=\frac{40.2}{2\pi}rev\\d=6.40rev$

for c)

$\omega=w_o+\alpha*t\\\omega=0+13.0rad/s^2*2.50s\\\omega=32.5rad/s$

because it started from rest the initial angular velocity is zero.

for d)

$v=r*\omega\\v=0.330m*32.5rad/s\\v=10.7m/s$