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ludmilkaskok [199]
3 years ago
9

What happens to some of the sun's energy that does not reach the earth's surface?

Physics
1 answer:
LenaWriter [7]3 years ago
4 0
Hello, 

Here is your answer:

The proper answer for this question is that they "get absorbed by the ozone layer".

If you need anymore help feel free to ask me!

Hope this helps!
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Use 3rd law to explain how a fish swims through water. Identify the force pairs and draw a diagram.
vovikov84 [41]
Well as the fish swims he pushes the water behind him which in return push him forward
5 0
3 years ago
Name the four fundamental fores at work inside an atom. Tell what each one does.​
STALIN [3.7K]

Answer:

Four fundamental forces are gravitational, electromagnetic, strong, and weak.

Explanation:

The gravitational and electromagnetic interactions, which produce significant long-range forces whose effects can be seen directly in everyday life and the strong and weak interactions, which produce forces at minuscule, subatomic distances and govern nuclear interactions.

6 0
2 years ago
Which force requires contact?
Minchanka [31]

Answer:

A

Explanation: A is a example of Air resistance force, which is a contact force.

8 0
3 years ago
Read 2 more answers
With fuel prices for combustible engine automobiles increasing, researchers and manufacturers have given more attention to the c
Alinara [238K]

Answer:

Then the difference of weight between the two cars are:

Δw = 14210 - 5292 = 8918 N

Explanation:

An object's weigh due to the gravitational attraction force of the earth is:

w = mg

            Where: m is the object's mass

                         g is the  gravitational acceleration in the surface earth

                         g = 9.8 m/s2

The the ultralight car's weight is:

w_{uc} = (540)(9.8)

w_{uc} = 5292 N

And the Honda Accord's weight is:

w_{HA} = (1450)(9.8)

w_{HA} = 14210 N

Then the difference of weight between the two cars are:

Δw = 14210 - 5292 = 8918 N

4 0
3 years ago
Determine the stopping distances for a car with an initial speed of 88 km/h and human reaction time of 2.0 s for the following a
seropon [69]

Explanation:

Given that,

Initial speed of the car, u = 88 km/h = 24.44 m/s

Reaction time, t = 2 s

Distance covered during this time, d=24.44\times 2=48.88\ m

(a) Acceleration, a=-4\ m/s^2

We need to find the stopping distance, v = 0. It can be calculated using the third equation of motion as :

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{-(24.44)^2}{2\times -4}

s = 74.66 meters

s = 74.66 + 48.88 = 123.54 meters

(b) Acceleration, a=-8\ m/s^2

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{-(24.44)^2}{2\times -8}

s = 37.33 meters

s = 37.33 + 48.88 = 86.21 meters

Hence, this is the required solution.

4 0
3 years ago
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