Answer:
H = 1/2 g t^2 where t is time to fall a height H
H = 1/8 g T^2 where T is total time in air (2 t = T)
R = V T cos θ horizontal range
3/4 g T^2 = V T cos θ 6 H = R given in problem
cos θ = 3 g T / (4 V) (I)
Now t = V sin θ / g time for projectile to fall from max height
T = 2 V sin θ / g
T / V = 2 sin θ / g
cos θ = 3 g / 4 (T / V) from (I)
cos θ = 3 g / 4 * 2 sin V / g = 6 / 4 sin θ
tan θ = 2/3
θ = 33.7 deg
As a check- let V = 100 m/s
Vx = 100 cos 33.7 = 83,2
Vy = 100 sin 33,7 = 55.5
T = 2 * 55.5 / 9.8 = 11.3 sec
H = 1/2 * 9.8 * (11.3 / 2)^2 = 156
R = 83.2 * 11.3 = 932
R / H = 932 / 156 = 5.97 6 within rounding
Answer:
25
Explanation:
Given:
1 can of concentrate requires 3 cans of water
Now,
Total ounces in 200 6-ounce cans = 1200 ounces
also,
for 1 can of concentrate requires 3 cans of water
thus,
for 12 ounces can water can required = 3 × 12 ounces = 36 ounces of cans
Thus,
total ounce of juice per can = 12 + 36 = 48 ounces per can
therefore,
the number of 12-ounce cans required are = 
or
= 
or
the number of 12-ounce cans required are = 25
Answer:
1) The plane of the loop is perpendicular to the magnetic field.
2) The magnetic flux is independent of the orientation of the loop.p
Explanation:
The flux is calculated as φ=BAcosθ. The flux is therefore the highest when the magnetic field vector is perpendicular to the plane of the loop We can also deduce that the flux is zero when there is no magnetic field part perpendicular to the loop When the angle reaches zero, the flux is in the limit because when the angle becomes zero, the cos is the maximum.
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