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Radda [10]
3 years ago
15

Amelia is driving her car down a residential street. She approaches a stop sign and applies her brakes. It takes the car a few s

econds to come to a complete stop. Which of the following terms best explains why Amelia's car does not stop instantaneously when she applies the brakes?
A. friction

B. magnetism

C. inertia

D. gravity
Physics
1 answer:
Natalka [10]3 years ago
5 0

I think this is d. gravity

This is because gravity stops everything from stopping right away hope i helped please give brainliest if im correct!

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Please help me understand this
zloy xaker [14]

Answer: Can't see the photo clearly.

6 0
2 years ago
A force AB of length 100m and weight 600N has its centre of gravity 4.0 m from the end, and lies on horizontal ground calculate
Stells [14]

Answer:

F = 24 N

Explanation:

In this exercise we have a bar l = 100 m with a center of gravity x = 4 m, which force is needed to lift it from the other end

Let's use the rotational equilibrium relationship, where we consider the counterclockwise rotations as positive and fix the reference system at the point closest to the center of gravity

           ∑ τ = 0

           F l -x W = 0

           F = \frac{x}{l} \  W

let's calculate

          F = \frac{4}{100}4/100 600

          F = 24 N

8 0
3 years ago
What is the gravitational force that two objects would feel if they are 3.5 meters apart? Object 1 has a mass of 10x10^5 kg and
polet [3.4K]

Answer:

1.63 N

Explanation:

F = GMm/r^2

  = (6.67x10^-11)(10x10^5)(3x10^5) / 3.5^2

  = 1.63 N  ( 3 sig. fig.)

6 0
3 years ago
What is the acceleration of an object that takes 20 sec to change from a speed of 200 m/s to 300 m/s ?
marin [14]

<u>Given</u><u>:</u>

  • initial velocity, u = 200 m/s

  • Final velocity, v = 300 m/s

  • Time taken, t = 20 sec

<u>To</u><u> </u><u>be</u><u> </u><u>calculated</u><u>:</u>

Calculate the acceleration of given object ?

<u>Formula</u><u> </u><u>used</u><u>:</u>

Acceleration = v - u / t

<u>Solution</u><u>:</u>

We know that,

Acceleration = v - u / t

☆ Substituting the values in the above formula,we get

Acceleration ⇒ 300 - 200 / 20

⇒ 100/20

⇒ 5 m/s²

5 0
4 years ago
A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction
Vaselesa [24]

Answer:

H=1020.12m

Explanation:

From a balance of energy:

\frac{m*Vo^2}{2} -mg*H=-Ff*d   where H is the height it reached, d is the distance it traveled along the ramp and Ff = μk*N.

The relation between H and d is given by:

H = d*sin(30)   Replace this into our previous equation:

\frac{m*Vo^2}{2} -mg*d*sin(30)=-\mu_k*N*d

From a sum of forces:

N -mg*cos(30) = 0    =>  N = mg*cos(30)   Replacing this:

\frac{m*Vo^2}{2} -mg*d*sin(30)=-\mu_k*mg*cos(30)*d   Now we can solve for d:

d = 2040.23m

Thus H = 1020.12m

6 0
3 years ago
Read 2 more answers
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