Answer: Can't see the photo clearly.
Answer:
F = 24 N
Explanation:
In this exercise we have a bar l = 100 m with a center of gravity x = 4 m, which force is needed to lift it from the other end
Let's use the rotational equilibrium relationship, where we consider the counterclockwise rotations as positive and fix the reference system at the point closest to the center of gravity
∑ τ = 0
F l -x W = 0
F = 
let's calculate
F =
4/100 600
F = 24 N
Answer:
1.63 N
Explanation:
F = GMm/r^2
= (6.67x10^-11)(10x10^5)(3x10^5) / 3.5^2
= 1.63 N ( 3 sig. fig.)
<u>Given</u><u>:</u>
- initial velocity, u = 200 m/s
- Final velocity, v = 300 m/s
<u>To</u><u> </u><u>be</u><u> </u><u>calculated</u><u>:</u>
Calculate the acceleration of given object ?
<u>Formula</u><u> </u><u>used</u><u>:</u>
Acceleration = v - u / t
<u>Solution</u><u>:</u>
We know that,
Acceleration = v - u / t
☆ Substituting the values in the above formula,we get
Acceleration ⇒ 300 - 200 / 20
⇒ 100/20
⇒ 5 m/s²
Answer:
H=1020.12m
Explanation:
From a balance of energy:
where H is the height it reached, d is the distance it traveled along the ramp and Ff = μk*N.
The relation between H and d is given by:
H = d*sin(30) Replace this into our previous equation:

From a sum of forces:
N -mg*cos(30) = 0 => N = mg*cos(30) Replacing this:
Now we can solve for d:
d = 2040.23m
Thus H = 1020.12m