Answer: Ecell = -0.110volt
Explanation:
Zn--->Zn^+2 + 2e^-.........(1) oxidation
Cu^2+ 2e^- --->Cu........(2)reduction
Zn + Cu^2+ ----> Cu + Zn^+2 (overall
For an electrochemical cell, the reduction potential set up is given by
E(cell) = E(cathode) - E(anode)
E(cell) = E(oxidation) - E(reduction)
E(cathode) = E(oxidation)
E(anode) = E(reduction)
Given that
E(oxidation) = -0.763v
E(reduction) = +0.337v
E(cell) = -0.763 - (+0.337)
E(cell) = -0.763- 0.337
E(cell) = -0.110volt
To balance a chemical reaction, we need to remember that the number of each atom in the reactant and the product side of the equation should be equal. So, from the reaction <span>P4(s) + Cl2(g) = PCl3(l), there are 4 P atoms in the reactant, the P atoms in the prodcut side should be 4 as well. We balance as follows:
</span> P4(s) + 6Cl2(g) = 4PCl3(l)
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Therefore, the coefficient of the PCl3 should be 4.
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