In the past mining companies were not made responsible for the clean-up of any of

Oxygen gas can be prepared by heating potassium chlorate according to the following equation:2KClO3(s)Arrow.gif2KCl(s) + 3O2(g)T

Eduardwww [97]

Answer:

Moles of potassium chlorate reacted = 0.2529 moles

The amount of oxygen gas collected will be 12.8675 g

Explanation:

(a)

We are given:

Vapor pressure of water = 17.5 mmHg

Total vapor pressure = 748 mmHg

Vapor pressure of Oxygen gas = Total vapor pressure - Vapor pressure of water = (748 - 17.5) mmHg = 730.5 mmHg

To calculate the amount of Oxygen gas collected, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 730.5 mmHg

V = Volume of the gas = 9.49 L

T = Temperature of the gas = $20^oC=[20+273]K=293K$

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

$730.5mmHg\times 9.49L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 293K\\\\n=\frac{730.5\times 9.49}{62.3637\times 293}=0.3794mol$

According to the reaction shown below as:-

$2KClO_3(s)\rightarrow 2KCl(s) +3O_2(g)$

3 moles of oxygen gas are produced when 2 moles of potassium chlorate undergoes reaction.

So,

0.3794 mol of oxygen gas are produced when $\frac{2}{3}\times 0.3794$ moles of potassium chlorate undergoes reaction.

<u>Moles of potassium chlorate reacted = 0.2529 moles</u>

(b)

We are given:

Vapor pressure of water = 17.5 mmHg

Total vapor pressure = 753 mmHg

Vapor pressure of Oxygen gas = Total vapor pressure - Vapor pressure of water = (753 - 17.5) mmHg = 735.5 mmHg

To calculate the amount of Oxygen gas collected, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 735.5 mmHg

V = Volume of the gas = 9.99 L

T = Temperature of the gas = $20^oC=[20+273]K=293K$

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

$735.5mmHg\times 9.99L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 293K\\\\n=\frac{735.5\times 9.99}{62.3637\times 293}=0.40211mol$

Moles of Oxygen gas = 0.40211 moles

Molar mass of Oxygen gas = 32 g/mol

Putting values in above equation, we get:

$0.037mol=\frac{\text{Mass of Oxygen gas}}{2g/mol}\\\\\text{Mass of Oxygen gas}=(0.40211mol\times 32g/mol)=12.8675g$

<u>Hence, the amount of oxygen gas collected will be 12.8675 g</u>

5 0

2 years ago

Find the number of moles in 3.62 x 1024 atoms of helium.

Makovka662 [10]

3.62x10^24/ 6.02x10^23= 6.013 moles to 3dp

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3 years ago

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Of the following which element is the heaviest? helium argon lithium aluminum

Georgia [21]

Answer:

Lithium

Explanation:

it is the only metal listed.

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3 years ago

What is the pH of a Koh solution that has [H+]=1.87×10^-13M

xenn [34]

PH=-log[H⁺]
pH=-log(1.87×10⁻¹³)
pH=12.72

I hope this helps. Let me know if anything is unclear.

7 0

2 years ago

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Atoms with the same number of protons but different masses (from different numbers of neutrons) are called:

____ [38]

Atoms with the same number of protons but different masses are called Isotopes.

<h3>What are Isotopes?</h3>

An isotope is one of two or more chemical elements that exist in different forms. Varied isotopes of an element have the same atomic number and protons in their nuclei, giving them the same atomic weight. However, each elemental isotope has a different amount of neutrons, which changes its atomic weight.

isobars - Isobars are atoms (nuclides) of several chemical elements that have diverse chemical characteristics but share the same physical characteristics. So, we may define isobars as elements with the same mass number but a different atomic number.

to learn more about isotopes go to -

https://brainly.in/question/1341808

#SPJ4

5 0

1 year ago