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GrogVix [38]
3 years ago
9

Two tuning forks produce sounds of wavelengths of 3.4 meters and 3.3 meters.

Physics
1 answer:
KengaRu [80]3 years ago
5 0

Answer:

Explanation:

wavelength, λ = 3.4 m

wavelength, λ' = 3.3 m

Speed, v = 340 m/s

f = v / λ = 340 / 3.4 = 100 Hz

f' = v / λ' = 340 / 3.3 = 103.03 Hz

Frequency of beat, n = f' - f = 103.03 - 100 = 3.03 Hz

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The speed of a wave is 40 m/s. If the wavelength is 80 centimeters, what is the frequency of the wave?
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<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

The speed of a wave is 40 m/s. If the wavelength is 80 centimeters, what is the frequency of the wave ?

<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>

<h3>Given:-</h3>

Velocity (V) = 40 m/s

Wavelength (\lambda) = 80 cm = 0.8 m

<h3>To Find:-</h3>

The frequency (F) of the wave.

<h2>Solution:-</h2>

We know,

\bf V \: = \: F \: × \: \lambda

40 = F × 0.8

F = \frac{40}{0.8}

F = 50

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3 years ago
Waves that hit a fixed boundary return to the starting point on the____
Jet001 [13]

Answer:

A: Opposite

Explanation:

From Newton's third law of motion, to every action there is an equal an opposite reaction. Thus, when the wave hits a fixed boundary, it is returned as a reflected wave to the starting point albeit on the other side.

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2 years ago
Which type of heat transfer takes place in gases by the movement of particles through a medium?
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Hope this answer helps!

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Two objects are moving downward at a speed of 3 cm/s. Object A has a mass of 2kg and Object B has a mass of 1kg. You want both o
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4 0
2 years ago
In your frame, a person is moving in the positive x-direction at a speed of 40,000 km / s. Suppose that a streetlamp located at
nexus9112 [7]

Answer:

proper time taken by the person is 9.911 × 10⁻⁵ s

Explanation:

speed of the person  in x- direction = 40,000 km/s

                                                           =  40,000 × 10³ m/s

                                                           =  4 × 10⁷ m/s

when the person just passes the street lamp is switched on which is at x =4 km

Lorentz factor = \gamma = \dfrac{1}{\sqrt{1-\dfrac{r^2}{c^2}}}

                                         = \dfrac{1}{\sqrt{1-\dfrac{(4 \times 10^7)^2}{(3 \times 10^8)2}}}

                                         = 1.009

time taken in your frame of reference,t =\dfrac{D}{v}

                                                                 =\dfrac{4}{40000} = 10 ^{-4}s

proper time  =t_0 = \dfrac{t}{\gamma}=\dfrac{10^{-4}}{1.009}= 9.911 \times 10^{-5} s

hence, proper time taken by the person is 9.911 × 10⁻⁵ s

5 0
3 years ago
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