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boyakko [2]
3 years ago
9

Do mechanical engineers use a lot of math

Physics
1 answer:
solmaris [256]3 years ago
8 0
Yes basic, calculus, and trig
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Science is the human endeavor to understand the natural world true or flase
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A rock of mass 200 g is attached to a 0.75 m long string and swung in a vertical plane.
Ainat [17]

Hello!

a) Assuming this is asking for the minimum speed for the rock to make the full circle, we must find the minimum speed necessary for the rock to continue moving in a circular path when it's at the top of the circle.

At the top of the circle, we have:

- Force of gravity (downward)

*Although the rock is still connected to the string, if the rock is swinging at the minimum speed required, there will be no tension in the string.

Therefore, only the force of gravity produces the net centripetal force:

\Sigma F = F_g\\\\F_c = F_g\\\\\frac{mv^2}{r} = mg

We can simplify and rearrange the equation to solve for 'v'.

\frac{v^2}{r} = g\\\\v^2 = gr\\\\v = \sqrt{gr}

Plugging in values:

v = \sqrt{9.8 * 0.75} = \boxed{2.711 m/s^}

b)
Let's do a summation of forces at the bottom of the swing. We have:
- Force due to gravity (downward, -)

- Tension force (upward, +)

The sum of these forces produces a centripetal force, upward (+).

\Sigma F = T - F_g\\\\F_c = T - F_g\\\\\frac{mv^2}{r} = T - mg

Rearranging for 'T":
T =   \frac{mv^2}{r} +  mg\\\\

Plugging in the appropriate values:
T =  \frac{(0.2)(2.711^2)}{(0.75)} + 0.2(9.8) = \boxed{3.92 N}

5 0
2 years ago
Read 2 more answers
A ray diagram is shown.
alexandr402 [8]

Answer:

  Z

Explanation:

The purple and yellow rays from the same point on the object are shown converging at point Z, where the image will be.

7 0
3 years ago
Can someone please help me ASAP
Serggg [28]

Answer:

distance = 6.1022 x10^16[m]

Explanation:

To solve this problem we must use the formula of the average speed which relates distance to time, so we have

v = distance / time

where:

v = velocity = 3 x 10^8 [m/s]

distance = x [meters]

time = 6.45 [light years]

Now we have to convert from light-years to seconds in order to get the distance in meters.

t = 6.45 [light-years]*365[\frac{days}{1light-year}]*24[\frac{hr}{1day}] *60[\frac{min}{1hr}]*60[\frac{seg}{1min} ] =203407200 [s]

Now using the formula:

distance = v * time

distance = (3*10^8)*203407200

distance = 6.1022 x10^16[m]

8 0
3 years ago
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