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Tema [17]
3 years ago
11

What is the best example of an experimental scientific investigation?

Chemistry
1 answer:
ivolga24 [154]3 years ago
7 0

Scientific investigation: The process in which scientist solve the question by using different systematic approach. It can be initiated in different ways.

Experimental Scientific investigation: The investigation in which scientist answer the question on the basis of experimental results. Experimental investigation includes both dependent and independent variables, and only one variable is tested at a time is possible.

The best example of an experimental scientific investigation is: when we placed a whole apple and apple slice under sun, and noted down how many days it will take to  rot in order to compare the break down of apple slice and whole apple.

Thus, option (B) is the correct answer.

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ANSWERIT AND YOU WILL BE MARKED THE BRAINLIEST
fgiga [73]

Answer:

The answer is definitely D

Explanation:

3 0
3 years ago
Read 2 more answers
Why melting point of Fe in blast furnace is lower than ellingham?
Kaylis [27]

Answer:

Because they are different oxides.

Explanation:

In both processes they are involve Iron Oxides, but in the case of Ellingham diagrams, it is consider the Iron in combination with oxygen to form FeO, so the melting point is around 1600  ºC. In the case of blast furnace, the Fe that is present in the ores, are primary the hematite (Fe2O3) and the magnetite (Fe3O4).

6 0
3 years ago
Calcium Carbide (CaC2) is an unusual substance that contains a carbon anion (C2 2- ). The reaction with water involves several s
rjkz [21]

The question is incomplete. The complete question is:

Calcium Carbide (CaC₂) is an unusual substance that contains a carbon anion (C₂²⁻). The reaction with water involves several steps that occur in rapid succession. CaC2 is a salt (notice that its name is similar to sodium chloride). When a salt dissolves in water, ions leave the crystal lattice and enter the aqueous (aq) solution. Write the relevant balanced chemical equation for the dissolution of CaC₂, in water.

Answer:

CaC₂(s) + 2H₂O(l) → Ca(OH)₂(aq) + C₂H₂(aq)

Explanation:

When a salt dissolves in water, it dissociates in its ions. In the Calcium Carbide, the cation is Ca⁺² and the anion is C₂²⁻, so the reaction is:

CaC₂(s) + 2H₂O(l) → Ca(OH)₂(aq) + C₂H₂(aq)

The base Ca(OH)₂ is soluble, so it will dissociate at Ca⁺ and OH⁻, but the C₂H₂ is stable and doesn't dissociate in the solution.

5 0
3 years ago
4th one<br> Mark the brainliest
ale4655 [162]

Answer:

1. The electronic configuration of X is: 1s2 2s2 sp6 3s2

2. The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6

3. The formula of the compound form by X and Y is given as: XY

Explanation:

For X to loss two electrons, it means X is a group 2 element. X can be any element in group 2. The electronic configuration of X is:

1s2 2s2 sp6 3s2

To get the electronic configuration of the anion of element Y, let us find the configuration of element Y. This is done as follows:

Y receives two electrons from X to complete its octet. Therefore Y is a group 6 element. The electronic configuration of Y is given below

1s2 2s2 2p4

The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6

The formula of the compound form by X and Y is given below :

X^2+ + Y^2- —> XY

Their valency will cancel out thus forming XY

4 0
3 years ago
How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f
BaLLatris [955]

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}

A is the resulting amount after t time

Ao is the initial amount = 50 mg

t= Elapsed time

t half is the half-life of the substance = 14.3 days

We replace the know values into the equation to have an exponential decay function for a 50mg sample

A=\text{ 50 }\times2^{\frac{-t}{14.3}}

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}

So, after 84 days the P-32 remaining will be 0.85 mg

4 0
1 year ago
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