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Dafna11 [192]
3 years ago
7

A simple pendulum consists of a mass M attached to a string oflength L andnegligible mass. For this system, when undergoing smal

loscillations,a) the frequency is proportional to the amplitude.b) the period is proportional to the amplitude.c) the frequency is independent of the mass M.d) the frequency is independent of the length L
Physics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

The frequency of the pendulum is independent of the mass on the end. (c)

This means that it doesn't matter if you hang a piece of spaghetti or a school bus from the bottom end.  If there is no air resistance, and no friction at the top end, and the string has no mass, then the time it takes the pendulum to swing from one side to the other <u><em>only</em></u> depends on the <u><em>length</em></u> of the string.

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Distance versus Displacement Worksheet
Umnica [9.8K]

when we find the distance we will add all the blocks so

distance = 6+6+4

distance = 14blocks

when we find the displacement we will add and minus too

As you can read he goes to the south 6 and to north 6 so he leave that place and back to the place again so the displacement is 0. and again he goes to the west 4 blocks so the displacement = <em><u>4blocks</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>west</u></em>

6 0
4 years ago
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Two identical satellites are in orbit about the earth. One orbit has a radius r and the other 2r. The centripetal force on the s
velikii [3]

Answer:

the centripetal force on the satellite in the larger orbit is _one fourth_ as that on the satellite in the smaller orbit.

Explanation:

Mass of satellite, m

orbit radius of first, r1 = r

orbit radius of second, r2  = 2r

Centripetal force is given by

F= \frac{mv^{2}}{r}

Where v be the orbital velocity, which is given by

v=\sqrt{gr}

So, the centripetal force is given by

F= \frac{mgr}}{r}}=mg

where, g bet the acceleration due to gravity

g=\frac{GM}{r^{2}}

So, the centripetal force

F= \frac{GMm}}{r^{2}}}

Gravitational force on the satellite having larger orbit

F= \frac{GMm}{4r^{2}} .... (1)

Gravitational force on the satellite having smaller orbit

F'= \frac{GMm}{r^{2}} .... (2)

Comparing (1) and (2),

F' = 4 F

So, the centripetal force on the satellite in the larger orbit is _one fourth_ as that on the satellite in the smaller orbit.

8 0
4 years ago
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Current would flow between them and they would receive a terrible shock.
5 0
3 years ago
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A student is asked to determine the work done on a block of wood when the block is pulled horizontally using an attached string.
Lerok [7]

Answer:

D. Graphing the force as a function of distance and calculating the area under the curve.

Explanation:

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3 years ago
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How was Mendeleev's table different from Meyer's table? A. Mendeleev did not arrange according to chemical properties. B. Meyer
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Answer: C. Meyer did not leave gaps while Mendeleev did.

Explanation: Mendeleev's table was table different from Meyer's table because Meyer did not leave gaps while Mendeleev did.

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3 years ago
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