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3 years ago

Example 7.3

Physics

1 answer:

marysya [2.9K]3 years ago

4 0

Answer:

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Consider this situation: A rope is used to lift an actor upward off the stage. Of the forces listed, identify which act upon the

Katarina [22]

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4 years ago

Read 2 more answers

You've learned about simple circuits and resistors at this point. So, let's talk about how we can power different circuits. Supp

DIA [1.3K]

Answer:

Explanation:

Total resistance of 2 bulb in series

= 100 +100 = 200 ohm

current in each bulb

= 9/200 = .045 A

In case of parallel combination of bulb

total resistance

= 100 x 100 / (100+100)

50 ohm

current in the main circuit

= 9 / 50 A

current in each bulb

= 9 / (2 x 50)

.09

So in the second case current is more , hence heat generated too will be more . So brightness too will be more.

First set ( in series ) will be dimmer.

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3 years ago

A spaceship, at rest in some inertial frame in space, suddenly needs to accelerate. The ship forcibly expels 103 kg of fuel from

Cerrena [4.2K]

Answer:

$V_s = 1.8*10^5m/s$

Explanation:

There is no external force applied, therefore there is a moment's preservation throughout the trajectory.

<em>Initial momentum = Final momentum. </em>

The total mass is equal to

$m_T= m_1 +m_2$

Where,

$m_1 =$ mass of ship

$m_2 =$ mass of fuell expeled.

As the moment is conserved we have,

$0=V_fm_2+V_sm_1$

Where,

$V_f =$ Velocity of fuel

$V_s =$ Velocity of Space Ship

Solving and re-arrange to $V_s$ we have,

$V_s = \frac{V_f m_2 }{m_1}$

$V_s = \frac{3/5c}{10^6}$

$V_s = 3.5*10^{-3}c$

Where c is the speed of light.

Therefore the ship be moving with speed

$V_s = \frac{3}{5}*10^{-3}*3*10^8m/s$

$V_s = 1.8*10^5m/s$

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3 years ago

A 90-kg astronaut is stranded in space at a point 6.0 m from his spaceship, and he needs to get back in 4.0 min to control the s

Stella [2.4K]

Momentum = 0.5 * 4 = 2
to conclude the man’s velocity after he throws the piece of equipment, divide this number by the man’s mass.

v = 2/90

This is about 0.0222 m/s. To know if he can move 6 meters at velocity in 4minutes, use the following equation.

d = v * t, t = 4 * 60 = 240 s
d = 2/90 * 240 = 5⅓ meters.

This is ⅔ of a meter from the spaceship. To know the velocity that he must have to move 6 meter, use the same equation.

6 = v * 240
v = 6/240
This is about 0.00416 m/s.
His final momentum = 90 * 6/240 = 2.25

To know the velocity of the package, divide this number by the mass of the package.
v = 2.25/0.5 = 4.5 m/s

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3 years ago

By what factor does the force required to stop a car increase if the initial speed is doubled and the stopping distance remains

mojhsa [17]

<span>Since the equation is F = ma the acceleration would change by a factor of 2, since a = v/2. The force would double.</span>

4 0

4 years ago