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3 years ago

Example 7.3

Physics

1 answer:

marysya [2.9K]3 years ago

4 0

Answer:

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true or false:acceleration toward the center of a curved or circular path is called gravitational acceleration.

nalin [4]

Nope. It's called 'centripetal' acceleration. The force that created it MAY be gravitational, but it doesn't have to be. For things on the surface of the Earth moving in circles, it's never gravity.

5 0

3 years ago

How many joules of work are done against a truck when a force of 50 N pushes it 1 kilometer away

ELEN [110]

Answer:

Work = 50,000 J

Explanation:

Work = force * distance

Given that,

force = 50N
Distance = 1km = 1000m

Work = 50 * 1000

Work = 50,000 J

8 0

2 years ago

URGENT!!!

madreJ [45]

Answer:

$f=6.97\times 10^{14}\ Hz$

Explanation:

Given that,

Wavelength, $\lambda=430\ nm=430\times 10^{-9}\ m$

We need to find the frequency of the violet light.

We know that the relation between frequency and wavelength is given by :

$f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{430\times 10^{-9}}\\\\f=6.97\times 10^{14}\ Hz$

So, the frequency of violet light is $6.97\times 10^{14}\ Hz$ .

7 0

3 years ago

Ten high-technology batteries are tested for 200 hours each. One failed at 20 hours; another failed at 140 hours; all others com

Bas_tet [7]

Answer:

Failure rate = 20%

MTBF = 880 hours

Explanation:

given data

batteries = 10

tested = 200 hours

one failed = 20 hours

another fail at = 140 hours

solution

we know that Mean Time between Failures is express as = (Total up time) ÷ (number of breakdowns) ....................1

so here Total up time will be

Total up time = 200 × 10

Total up time = 2000

and here

Number of breakdown = 1 at 20 hour and another at 140 hour = 2

so it will be = (Total up time) ÷ (number of breakdowns) .......2

= $\frac{2000}{2}$ = 1000

so here gap between occurrences is

gap between occurrences= 140 - 20

gap between occurrences = 120 hour

and

MTBF will be

MTBF = 1000 - 120

MTBF = 880 hours

and

Failure rate (FR) will be

Failure rate (FR) = 1 ÷ MTBF ................3

Failure rate (FR) = R÷T ......................4

as here R is the number of failures and T is total time

so Failure rate (FR) = 20%

4 0

3 years ago

If two objects of the same size move through the air at different speeds, which encounters the greater air resistance?a. The fas

blagie [28]

Answer:

Option A is correct.

(The faster object encounters more resistance)

Explanation:

Option A is correct. (The faster object encounters more resistance)

Air resistance depends on various factors:

Speed of the object
Cross-sectional area of the object
Shape of the object

Formula:

$F=\frac{1}{2}C_d\rho A v^{2}$

As the speed of the object increases the amount of Air resistance/drag increases on the object, as the above formula shows direct relation between Air resistance/drag and velocity i.e F ∝ v^2.

6 0

3 years ago