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2 years ago

Example 7.3

Physics

1 answer:

marysya [2.9K]2 years ago

4 0

Answer:

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What is the specific heat of water? A. 1.00 J/gºC

Leona [35]

Answer:

B 4.18J\g degree C is the specific heat of water

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2 years ago

Which elements will bond ionically with barium such that the formula would be written as BaX2? A) Nitrogen, chlorine, and sodium

erma4kov [3.2K]

The answer would be:

B. Chlorine, iodine and Fluorine

Barium has 2 valence electrons. To satisfy the BaX₂ , this would mean that Barium will need to give one of each of its electrons. The elements that need 1 electron would be those that have 7 valence electrons to complete the octet. These elements would fall in group 7 or halogens. Chlorine, iodine and fluorine are all in Group 7, so this would be the best choice.

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3 years ago

Read 2 more answers

An electron passes location < 0.02, 0.04, -0.06 > m and 5 us later is detected at location < 0.02, 1.62,-0.79 > m (1

hram777 [196]

Answer:

(a)

Average velocity = < 0, 316000, 146000> m/s

(b) < 0, 2.844, 1.314 > m

Explanation:

r1 = < 0.02, 0.04, - 0.06 > m

r2 = < 0.02, 1.62, - 0.79 > m

time, t = 5 micro second = 5 x 10^-6 s

(a) Average velocity is defined as the ratio of total displacement to the total time taken.

Displacement = r = r2 - r1

r = < 0.02 - 0.02, 1.62 - 0.04, - 0.79 + 0.06 > m

r = < 0, 1.58, - 0.73 > m

So. Average velocity = $\frac{< 0, 1.58, - 0.73 >}{5 \times 10^{-6}}$

Average velocity = $< 0, 316000, 146000> m/s$

Average velocity = < 0, 316000, 146000> m/s

(b)

Distance = velocity x time

Here time, t = 9 micro second

d = < 0, 316000, 146000> x 9 x 10^-6 m

d = < 0, 2.844, 1.314 > m

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3 years ago

Tell me all about acids and bases (NO GOOGLE SEARCH)

aleksklad [387]

Acids are danger so stay away

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3 years ago

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A 113 kg man sits on the stern of a 6.3 m long boat. The prow of the

Usimov [2.4K]

Answer:

m = 105.37 kg

Explanation:

We are given;

Mass of man; m = 113 kg

Length of boat = 6.3m

Now, The position of the center of mass will not change during the motion of the man.

Thus,

X_g,i = X_g,f

So,

[113(6.3) + ma]/(113 + m) = [113(3.26) + m(a +3.26)]/(113 + m)

113 + m will cancel on both sides to give;

113(6.3) + ma = [113(3.26) + m(a +3.26)]

711.9 + ma = 368.38 + ma + 3.26m

ma will cancel out to give;

711.9 - 368.38 = 3.26m

343.52/3.26 = m

m = 105.37 kg

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3 years ago