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VARVARA [1.3K]
3 years ago
11

Alex is walking down towards the pharmacy from his home. He has to make several stops along the way. He walks to the pet store 5

blocks east of his house, then walks 10 blocks north to the pharmacy. What is the total displacement Alex walks during this whole trip?
Physics
1 answer:
Lelechka [254]3 years ago
5 0

Let east be positive X direction and north be positive Y direction.

Displacement in east direction = 5 blocks = X component of displacement =X

Displacement in north direction = 10 blocks = Y component of displacement =Y

Total displacement=\sqrt[2]{X^2+Y^2} =\sqrt[2]{5^2+10^2}=\sqrt[2]{125}= 11.18 (approx) blocks

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alexandr402 [8]
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3 0
3 years ago
A tank whose bottom is a mirror is filled with water to a depth of 19.6 cm. A small fish floats motionless a distance of 6.40 cm
ANEK [815]

Answer:

A. 4.82 cm

B. 24.66 cm

Explanation:

The depth of water = 19.6 cm

Distance of fish  = 6.40 cm

Index of refraction of water = 1.33

(A). Now use the below formula to compute the apparent depth.

d_{app} = \frac{n_{air}}{n_{water}} \times d_{real} \\= \frac{1}{1.33} \times 6.40 \\= 4.82 cm.

(B). the depth of the fish in the mirror.

d_{real} = 19.6 cm + (19.6 cm – 6.40 cm) = 32.8 cm

Now find the depth of reflection of the fish in the bottom of the tank.

d_{app} = \frac{n_{air}}{n_{water}} \times d_{real} \\d_{app} = \frac{1}{1.33} \times 32.8  = 24.66\\

4 0
3 years ago
HURRY What happened when the speed was increased?
sp2606 [1]
What happened to what?
7 0
3 years ago
Read 2 more answers
A 100100​-watt ​[W] motor ​(6060​% ​efficient) is available to raise a load 1010 meters​ [m] into the air. If the task takes 808
dlinn [17]

Answer:

m = 48.93kg

The load is 48.93kg.

Explanation:

Given;

Power P = 100watts

Efficiency e = 60% = 0.60

distance d = 10 m

time taken t = 80 s

Acceleration due to gravity g = 9.81m/s

Workdone W can be expressed as;

W = ePt = Fd = mgd

ePt = mgd

Making m the subject of formula;

m = ePt/gd

Substituting the values;

m = (0.60×100×80)/(9.81×10)

m = 48.93kg

The load is 48.93kg.

4 0
3 years ago
If 2000 kg cannon fires 2 kg projectile having muzzle velocity 200 m/s then the KINETIC ENERGY of the projectile will be ("E4" m
nordsb [41]

Answer:

K=4\times 10^4\ J

Explanation:

Given that,

Mass of cannon is,M =  2000 kg

Mass of projectile, m = 2 kg

Velocity of the projectile, v = 200 m/s

We need to find the kinetic energy of the projectile. We know that the formula for the kinetic energy of an object is given by :

K=\dfrac{1}{2}mv^2\\\\\text{Putting all the values, we get}\\\\K=\dfrac{1}{2}\times 2\times (200)^2\\\\K=40000\ J

or

K=4\times 10^4\ J

So, the kinetic energy of the projectile will be 4\times 10^4\ J.

7 0
3 years ago
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