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guapka [62]
3 years ago
14

How many atoms are in 3.5 moles of He?

Chemistry
1 answer:
Volgvan3 years ago
4 0

Answer:

The answer is 2.107 × 10²⁴ He atoms

Explanation:

To find the number of atoms given the number moles we use the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

N = 3.5 × 6.02 × 10²³

We have the final answer as

<h3>2.107 × 10²⁴ He atoms</h3>

Hope this helps you

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Reactivity and flammability are are examples of properties.​
nika2105 [10]

Answer:

they are eamples of chemical properties

Explanation:

flammibility is the chemical makeup of the element that makes it flamable and reactivitie is the chemical makeup of an element that is able to reacte to another element

3 0
3 years ago
What is the main idea of this paragraph? (The image gives you a hint...) Select an answer Carbon is the building block of the un
Crank

Answer:

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3 0
3 years ago
How many moles of carbon are in 7.00 x 1023 atoms of carbon?
Andru [333]

Answer:

<h2>1.16 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{7}{6.02}  \\  = 1.162790....

We have the final answer as

<h3>1.16 moles</h3>

Hope this helps you

8 0
3 years ago
Given the following data in the Determination of Molar Mass of CO2 lab : Mass (before rxn): test tube HCl(aq) stir bar capsule 2
RSB [31]

Answer:

.259 g

Explanation:

PV = nRT

n = PV / RT

= .986 x 0.144 / .082 x 293.6

= .005897 moles

= .005897 x 44 g

= .259 g

3 0
3 years ago
What volume (in mL) of 0.250 M HCI would be
Nitella [24]

Answer: 1820 mL (to 3 sf)

Explanation:

The atomic mass of aluminum is 26.9815385 g/mol, so 4.10 g of aluminum is equal to 4.10/26.9815385 = 0.15195575300497 moles of Al.

From the coefficients of the equation, we know that for every 2 moles of aluminum consumed, 6 moles of HCl are consumed.

So, this means we need 0.15195575300497(6/2) = 0.45586725901491 moles of HCl.

Substituting into the molarity formula,

  • 0.250 = 0.45586725901491/(liters of HCl)
  • liters of HCl = 0.45586725901491/0.250
  • liters of HCl = 1.8234690360596 L = 1820 mL (to 3 sf)
4 0
2 years ago
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