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Genrish500 [490]
3 years ago
8

Propane, C3H8, consists of ________________ bonds and it can be expected to dissolve in hexane and to not dissolve in water.

Chemistry
1 answer:
PtichkaEL [24]3 years ago
4 0

Non-polar covalent

Explanation:

Propane is made up of non-polar covalent bonds and it can be expected to dissolve in hexane and to not dissolve in water.

Propane is an hydrocarbon gas.

It forms by sharing of electrons between two atoms with very low electronegativity differences.

This differences results in equal sharing of the shared electron. Therefore they form a non-polar covalent bond.

Water is a polar covalent compound and cannot dissolve compounds that are not polar like propane.

Propane will only dissolve in a like substance like hexane which is equally non-polar.

learn more:

Covalent compounds brainly.com/question/3109255

#learnwithBrainly

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In science, observations are objective, but intereroes are subjective. True or False?
Fed [463]

Answer:

the answer is False I hope this helps

8 0
3 years ago
For which of the processes below will δs be a positive number? 1) ch4(g) → ch4(l) 2) n2h4(g) → n2(g) + 2h2(g) 3) h2o(s) → h2o(g)
Shalnov [3]

The entropy of the gaseous substance is more in comparison to the liquid or solid form of the same substance at same temperature and pressure conditions.

More is the number of particles more will be the entropy of the system.

In the first chemical reaction, CH₄ (g) → CH₄ (l)

Since, the reactants are in gaseous phase and the products are in liquid phase, the entropy is decreasing during the reaction.

In the second chemical reaction,

N₂H₄ (g) → N₂ (g) + 2H₂ (g)

Since, one mole of the reactant in gaseous phase is decomposing to produce three moles of product in gaseous phase, the entropy is increasing during the reaction.

In the third chemical reaction, H₂O  (s) → H₂O (g)

Since, the reactant is in solid phase and product are in gaseous phase. The entropy is increasing during the reaction.

Thus, the entropy is increasing in the 2nd and 3rd reactions.


3 0
3 years ago
The attraction between molecules of methane in the liquid state is primarily due to
ivanzaharov [21]

Answer:

Attraction between molecules of methane in liquid state is primarily due to "London dispersion force".

Explanation:

Methane is a non-polar and aprotic molecule. Hence there is no dipole moment in methane as well as no chance of hydrogen bonding formation by methane.

We know that all molecules contain electrons. Therefore transient dipole arises in every molecule due to revolution of electrons around nucleus in a non-circular orbit. Hence an weak intermolecular attraction force is always present in every molecule as a result of this which is termed as "London dispersion force".

So, attraction between molecules of methane in liquid state is primarily due to "London dispersion force".

5 0
4 years ago
Considering the temperature vs. time graph below, how does the temperature at the beginning of a change of state
katen-ka-za [31]

Answer:

always the same

Explanation:

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5 0
3 years ago
Pls 50 points right answer gets brainliest
GuDViN [60]

Answer:

thermal energy: the part of total internal energy that can be transferred (a portion of the kinetic energy)

heat is the thermal energy that flows from one substance to another due to a temperature difference.

Thermal energy is measured in temperature change.

Thermal energy transfer stops when thermal equilibrium is achieved (Both substances at the same temperature).

conduction: Transfer of thermal energy through a solid object like heat transferring up a metal spoon from a hot cup of coffee.

convection: the transfer of thermal energy due to the movement of a liquid or gas caused by differences in temperature. Only in a fluid (liquid or gas). Breezes, ocean currents.

radiation: Transfer energy with or without matter. Warming from the Sun, microwave oven.

7 0
3 years ago
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