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77julia77 [94]
4 years ago
9

An object of mass 12kg is held at a weight of 5m above the ground for 30s. Calculate the workdone during this period.​

Physics
1 answer:
daser333 [38]4 years ago
5 0

Answer:

0 J

Explanation:

Work = force × distance

Since the object isn't moved, the distance is 0.  So the work is 0.

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Would you be doing more work going up the stairs twice as fast?
SSSSS [86.1K]
If you use the stairs at normal speed, you will survive longer, and go up higher.
When going up the stairs twice as fast, you lose energy more quickly, but height would remain the same.
7 0
3 years ago
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What is the mass of a truck if it is accelerating at a rate of 5 m/s2 and hits a parked car with a
sineoko [7]

Answer:

<h3>The answer is 2800 kg</h3>

Explanation:

The mass of the truck can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{14000}{5}  \\

We have the final answer as

<h3>2800 kg</h3>

Hope this helps you

5 0
3 years ago
At one instant of time a rocket is traveling in outer space at 2500m/s and is exhausting fuel at a rate of 100 kg/s. If the spee
lawyer [7]

Thrust is a reaction force described quantitatively by Newton's third law. When a system expels or accelerates mass in one direction, the accelerated mass will cause a force of equal magnitude but opposite direction on that system. Mathematically can be written as,

T = v\frac{dm}{dt}

Here,

v = speed of the exhaust gases measured relative to the rocket.

\frac{dm}{dt}= Rate of change of mass with respect to time

Our values are given as,

v = 1500m/s

\frac{dm}{dt} = 100kg/s

Replacing we have that

T = 1500*100

\therefore T = 1.5*10^5N

7 0
3 years ago
What direction does centripetal acceleration point?
Nesterboy [21]

Answer:

Inward

Explanation:

As the centripetal force acts upon an object moving in a circle at constant speed, the force always acts inward as the velocity of the object is directed tangent to the circle. This would mean that the force is always directed perpendicular to the direction that the object is being displaced. hope this helps :)

3 0
3 years ago
Please help<br><br> What is the magnitude of the normal force on the bag?<br> Answer in units of N.
Viefleur [7K]

Answer:

41.576 N

Explanation:

Resolving force in the inclined plane in the x and y directions gives us;

F_x = mg sin θ

F_y = mg cos θ

Thus;

F_x = 4.8 × 9.81 × sin 28

F_x = 22.106 N

F_y = 4.8 × 9.81 × cos 28

F_y = 41.576 N

We can use Newton's second law to find the normal force.. Thus;

N - F_y = 0.

Where N is normal force;

N = 41.576 N

6 0
3 years ago
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