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lutik1710 [3]
3 years ago
9

When an ionic compound dissolves in water:

Chemistry
1 answer:
Airida [17]3 years ago
8 0

Answer:

d. each of the above (A, B, and C) occurs.

Explanation:

When an ionic species dissolves in water , the ionic compound dissociates into cation and anion , and the cation interacts with the negative end of the water molecules , and the anion interacts with the positive end of the water molecule .

During the process of dissolution , the interaction between , solvent - solute overcome the interaction between solute - solute molecules .

Hence , From the question , all the statement given are correct .

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Why does Earth rotate?
sleet_krkn [62]

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With respect to the categories of assets, liabilities, and stockholders' equity presented on the balance sheet (statement of fin
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4 0
3 years ago
| A solution containing 4.48 ppm KMnO4 exhibits
Artist 52 [7]

Answer:

Molar absorptivity or molar extinction co-effecient = 2120.14 cm⁻¹M⁻¹

Explanation:

First convert Concentration from ppm inM or mol/l

⇒ Molar mass of KMnO₄ = 158.03 g

⇒ 4.48 ppm = 4.48 mg/l = 4.48 x 10⁻³ g/l

⇒ Molarity = \frac{4.48 X10^{-3} }{158.03X 1(lit)} = 2.83 x 10⁻⁵ molar

Absorbance (A) = - log(T)     ( T = % transmittance)

                          = - log(0.859)

                          = 0.06

According to Lambert Beer's law

     

                 ε = \frac{A}{C X l}

      or,      ε = \frac{0.06}{2.83 X 10^{-5}X1 cm }

      or,      ε = 2120.14 cm⁻¹M⁻¹

Where

    ε = Molar absorptivity

    A = absorbance

    C = Molar concentration of KMnO₄ solution

     l = length  

6 0
3 years ago
Calculate the cfse for a d^3 system in an octahedral field in units of ∆_o. In other words, do not enter "∆_o" with your answer.
Rudik [331]

Magnetic moment (spin only) of octahedral complex having CFSE=−0.8Δo and surrounded by weak field ligands can be : Q

To answer this, the Crystal Field Stabilization Energy has to be calculated for a (d3 metal in both configurations. The geometry with the greater stabilization will be the preferred geometry. So for tetrahedral d3, the Crystal Field Stabilization Energy is: CFSE = -0.8 x 4/9 Δo = -0.355 Δo.

[Co(CN)64-] is also an octahedral d7 complex but it contains CN-, a strong field ligand. Its orbital occupancy is (t2g)6(eg)1 and it therefore has one unpaired electron. In this case the CFSE is −(6)(25)ΔO+(1)(35)ΔO+P=−95ΔO+P.

The crystal field stabilization energy (CFSE) (in kJ/mol) for complex, [Ti(H2O)6]3+. According to CFT, the first absorption maximum is obtained at 20,3000cm−1 for the transition.

To learn more about crystal field stabilization energy  visit:brainly.com/question/29389010

#SPJ4

8 0
1 year ago
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