Answer:
0.08kg
Explanation:
Given parameters:
Temperature of water = 100°C
Quantity of heat released = 180414.08J
Unknown:
Quantity of water condensed = ?
Solution:
This is simple phase change process without any attendant change in temperature.
To solve this problem, use the formula below;
H = mL
H is the heat released
m is mass
L is the latent heat of condensation of water = 2260 kJ/kg
Insert the parameters and solve;
180,414.08 = m x 22.6 x 10⁵ J/kg
m =
= 0.08kg
Answer:
ptotal=pA+pB+pC
Explanation:
it is defined as the sum le the pressures le each individual gas ^
Explanation:
Given parameters:
Mass of sample = 235g
Molecular mass of sample = 128.1g
Empirical formula = CH₂O
Unknown:
Mass of each element in the sample = ?
Solution:
To solve this problem, we must know that the empirical formula of any compound is the simplest ratio of the atoms it contains. This is not the true formula of the compound.
Molecular formula = (Empirical formula)ₙ
Let us find the molecular mass of the sample;
CH₂O = 12 + 2(1) + 16 = 30g
128.1 = (30)n
n = 4
The molecular formula of the compound is; (CH₂O)₄ = C₄H₈O₄
Now to find the grams of each element in the sample;
Express the molecular mass of each element and that of the compound as a fraction and multiply with the given mass;
For C;
= 88.06g
H;
= 14.68g
O:
= 117.41g
learn more:
Mass composition brainly.com/question/3018544
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The H2 produced in a chemical reaction is collected through water in a eudiometer. The pressure (kPa) of the H2 gas is 98.89 kPa
The total pressure in a chemical reaction is the total sum of the partial pressure and the vapor pressure of the chemical substances taking place in the chemical reaction.
- Total pressure = partial pressure of H₂ gas + vapor pressure of H₂O
∴
The vapor pressure of H₂ gas = Total pressure in the eudiometer - partial pressure of H₂O
Given that:
- The total pressure in the eudiometer = 101.3 kPa
- The partial pressure of H₂O = 2.41 kPa
The vapor pressure of H₂ gas = 101.3 kPa - 2.41 kPa
The vapor pressure of H₂ gas = (101.3 - 2.41) kPa
The vapor pressure of H₂ = 98.89 kPa
Therefore, we can conclude that the vapor pressure of H₂ is 98.89 kPa.
Learn more about partial pressure here:
brainly.com/question/14281129?referrer=searchResults