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a_sh-v [17]
2 years ago
6

Choose all the answers that apply.

Chemistry
2 answers:
blondinia [14]2 years ago
4 0
As atomic Number is number of protons Or number of electrons so
N has 7 electrons
Neutrons= Mass no.- Atomic Number
= 14-7
N has 7 neutrons
N doesn’t have 7 electron shells because shell 1 can hold 2 electrons and shell 2 can hold 8 electrons
It doesn’t have 23 neutrons and 14 electrons

So, Seven Electrons and seven neutrons is correct
photoshop1234 [79]2 years ago
3 0
Seven electrons. The atomic number of a element is also the amount of protons and electrons it has.
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At 35.0°c and 3.00 atm pressure, a gas has a volume of 1.40 l. what pressure does the gas have at 0.00°c and a volume of 0.950 l
Leona [35]

Answer : The pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

Solution :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 3 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 1.40 L

V_2 = final volume of gas = 0.950 L

T_1 = initial temperature of gas = 35^oC=273+35=308K

T_2 = final temperature of gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{3atm\times 1.40L}{308K}=\frac{P_2\times 0.950L}{273K}

P_2=3.918atm

Therefore, the pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

4 0
3 years ago
Read 2 more answers
What is the boiling point of water at an elevation of 1.55×104 ft ?
horsena [70]
The computation for this problem is:
(1.55x10^4 / 1.0x10^3) x 19.8 mm Hg
= 15.5 x 19.88 mm Hg
= 308.14 mm Hg decrease 
= 308.14 x 0.05 C = 15.407 deg C 
deduct this amount to 100
100 – 15.407 = 84.593 C 
ANSWER: 85 deg C (rounded to 2 significant figures)
4 0
3 years ago
Can someone help me please
almond37 [142]

Answer:D

Explanation:

  1. Use the vertex form, y=a(x−h)2+ky=a(x-h)2+k, to determine the values of aa, hh, and kk.a=14a=14h=6h=6k=1k=1Find the vertex (h,k)(h,k).(6,1)(6,1)Find pp, the distance from the vertex to the focus.
  2. Find the distance from the vertex to a focus of the parabola by using the following formula.14a14aSubstitute the value of aa into the formula.14⋅1414⋅14Simplify.
  3. Combine 4 and 1/4 .1 /4/4
  4. Simplify by dividing numbers
  5. Divide 4 by 44.1/1Divide 1 by 1/1.
  6. Y=0
  7. The Answer is D
5 0
2 years ago
How many moles of hydrogen atoms are there in 1.25 x 1025 molecules of ethane? (C2H6)
krek1111 [17]

Answer:

124.56 moles of Hydrogen atoms.

Explanation:

We'll begin by calculating the number of moles of ethane that contains 1.25×10²⁵ molecules. This can be obtained as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10²³ molecules. This implies that 1 mole of ethane also contains 6.02x10²³ molecules.

Thus, 6.02x10²³ molecules are present in 1 mole of ethane.

Therefore, 1.25×10²⁵ molecules are present in = 1.25×10²⁵/6.02x10²³ = 20.76

Therefore, 20.76 moles of ethane contains 1.25×10²⁵ molecules.

Finally, we shall determine the number of mole of Hydrogen in 20.76 moles of ethane. This can be obtained as follow:

Ethane has formula as C2H6.

From the formula, 1 mole of ethane, C2H6 contains 6 moles of Hydrogen atoms.

Therefore, 20.76 moles of ethane will contain = 20.76 × 6 = 124.56 moles of Hydrogen atoms.

Therefore, 1.25×10²⁵ molecules of ethane contains 124.56 moles of Hydrogen atoms.

7 0
3 years ago
Freon-12, CF2Cl2, which has been widely used in air conditioning systems, is considered a threat to the ozone layer in the strat
Vilka [71]

Answer:

The root mean squared velocity for CF2Cl2 is  v_{rms}= 207.06 m/s

Explanation:

From the question we are told that

         The temperature is T = -65 ^oC = -65+273 = 208K

Root Mean Square velocity is mathematically represented as

      v _{rms} = \sqrt{\frac{3RT}{MW} }

 Where  T is the temperature

              MW is the molecular weight of gas

              R is the gas constant with a value of  R = 8.314 JK^{-1} mol^{-1}

For  CF2Cl2 its molecular weight is  0.121 kg/mol

     Substituting values

  v_{rms} = \sqrt{\frac{3 * 8.314 *208}{0.121} }

          v_{rms}= 207.06 m/s

5 0
3 years ago
Read 2 more answers
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