Answer:
Atoms
Explanation:
This is also a form of molucules
Answer:
The Independent variable is the variable which does not rely of the other variables. It stays the same.
The Dependent variable is the variable that is measured or changed.
Explanation:
The Independent variable is usually the x value of a table or graph
the Dependent variable is usually the y value of a table or graph
I hope this helps!
Yes , the chemist can answer if the compound in K2O or K2O2
The chemical formula and composition of both the compounds is entirely different. The compound K2O2 has an additional molecule of oxygen than K2O and hence will have have higher molecular mass.
In the compound K2O
molecular mass= 2x 39+16 =94
mass ratio of K in compound= 78/94 = 0.830
In the compound K2O2
molecular mass= 2x 39+16X2 =110
mass ratio of K in compound= 78/110 = 0.710
and hence by the required ratio while extracting K , the chemist may know if the compound is K20 or K2O2
If the ratio is anything different from 0.830 and 0.710 then the compund will be something different
#SPJ9
<em>Answer</em><em>:</em>
<em>Glycolysis</em>
<em>E</em><em>xplanation</em><em> </em><em>:</em>
Glycolysis is the first step in the breakdown of glucose to extract energy for cell metabolism.Many living organisms carry out glycolysis as part of their metabolism. Glycolysis takes place in the cytoplasm of most prokaryotic and all eukaryotic cells.
Answer:
![K_{c} = [\text{C}]^{2}[\text{[D]}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5B%5Ctext%7BC%7D%5D%5E%7B2%7D%5B%5Ctext%7B%5BD%5D%7D)
Explanation:

The general formula for an equilibrium constant expression is
![K_{c} = \dfrac{[\text{Products}]}{[\text{Reactants}]}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cdfrac%7B%5B%5Ctext%7BProducts%7D%5D%7D%7B%5B%5Ctext%7BReactants%7D%5D%7D)
Solids and liquids are not included in the equilibrium constant expression.
Thus, for this reaction,
![K_{c} = [\textbf{C}]^{\mathbf{2}}\textbf{[D]}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5B%5Ctextbf%7BC%7D%5D%5E%7B%5Cmathbf%7B2%7D%7D%5Ctextbf%7B%5BD%5D%7D)