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yanalaym [24]
3 years ago
12

PLEASE HELP!!!!!!!!!!!

Chemistry
1 answer:
Amiraneli [1.4K]3 years ago
4 0

Answer:

I believe your answer would be grams.

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Using the system of rules for naming binary acids and naming other binary covalent molecules​
ANEK [815]

Answer:

Atoms

Explanation:

This is also a form of molucules

3 0
3 years ago
What is the definition of an independent and dependent variable?
sladkih [1.3K]

Answer:

The Independent variable is the variable which does not rely of the other variables. It stays the same.

The Dependent variable is the variable that is measured or changed.

Explanation:

The Independent variable is usually the x value of a table or graph

the Dependent variable is usually the y value of a table or graph

I hope this helps!

3 0
3 years ago
A chemist can determine the mass of K in a sample of known mass that consists of either pure K2O or pure K2O2. From this informa
Arte-miy333 [17]

Yes , the chemist can answer if the compound in K2O or K2O2

The chemical formula and composition of both the compounds is entirely different. The compound K2O2 has an additional molecule of oxygen than K2O and hence will have have higher molecular mass.

In the compound K2O

molecular mass= 2x 39+16 =94

mass ratio of K in compound= 78/94 = 0.830

In the compound K2O2

molecular mass= 2x 39+16X2 =110

mass ratio of K in compound= 78/110 = 0.710

and hence by the required ratio while extracting K , the chemist may know if the compound is K20 or K2O2

If the ratio is anything different from 0.830 and 0.710 then the compund will be something different

#SPJ9

5 0
2 years ago
In which part of the cell is the majority of the energy released from the breakdown of glucose
Vladimir [108]

<em>Answer</em><em>:</em>

<em>Glycolysis</em>

<em>E</em><em>xplanation</em><em> </em><em>:</em>

Glycolysis is the first step in the breakdown of glucose to extract energy for cell metabolism.Many living organisms carry out glycolysis as part of their metabolism. Glycolysis takes place in the cytoplasm of most prokaryotic and all eukaryotic cells.

7 0
3 years ago
Read 2 more answers
Write the equilibrium-constant expression for the reactionA(s)+3B(l)↽−−⇀2C(aq)+D(aq)A(s)+3B(l)↽−−⇀2C(aq)+D(aq)in terms of [A], [
Ilia_Sergeevich [38]

Answer:

K_{c} = [\text{C}]^{2}[\text{[D]}

Explanation:

\rm A(s)+3B(l) \, \rightleftharpoons \, 2C(aq)+D(aq)

The general formula for an equilibrium constant expression is

K_{c} = \dfrac{[\text{Products}]}{[\text{Reactants}]}

Solids and liquids are not included in the equilibrium constant expression.

Thus, for this reaction,  

K_{c} = [\textbf{C}]^{\mathbf{2}}\textbf{[D]}

3 0
3 years ago
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